Answer:
A. Initially, there were 12 deer.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. After 15 years, there will be 410 deer.
D. The deer population incresed by 30 specimens.
Step-by-step explanation:

The amount of deer that were initally in the reserve corresponds to the value of N when t=0


A. Initially, there were 12 deer.
B. 
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. 
C. After 15 years, there will be 410 deer.
D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:
ΔN=N(15)-N(10)
ΔN=410 deer - 380 deer
ΔN= 30 deer.
D. The deer population incresed by 30 specimens.
To start, first distribute the x's to their expressions. This would look like this:
(x*x+2*x)+(x*x+x*3)=x^2+2x+x^2+3x
Then, you combine like terms or simplify, and you get an answer of 2x^2+5x
If you are asking about the percent then it would be 83.33%
<h2>
Explanation:</h2>
According to the chain rule, if we have a function:

The derivative at a point
will be:

We know that:

10450-270x=?
x=15
10450-270(15)=?
10450-4050=6400
there is 6400ml left in the tank after 15 minutes