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2 years ago

Evaluate 1 1/4 x 6 giving your answer as a mixed number in simplest form.

Mathematics

1 answer:

Genrish500 [490]2 years ago

7 0

Answer:

7 1/2

Step-by-step explanation:

First remember the rule to multiply fractions, you gots to have fractions; so convert 1 1/4 into a mixed number. To do this, multiply 1 by 4, then add 1. It equals 5/4.

Next multiply 5/4 by 6. You can "cross simplify" to make this problem easier and you will the the simplest form. To cross simplify, divide 6 and 4 by 2. The new thing is 5/2 times 3. This equals 15/2.

Divide but don't turn into decimal. 7 remainder 1 the divisor is 2.

Put them together 7 1/2

Final answer 7 1/2

Hope this helps

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RSB [31]

Answer:

7/8

Step-by-step explanation:

To find: number which represents the expression

Solution:

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2 years ago

Choose some numbers to compare to 55 use = and <,> WHAT NUMBERS COMPARE TO 55

horrorfan [7]

There's literally unlimited answers but here are some simple ones.

5 x 11 = 55

55 = 55

55 > 54

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3 years ago

Can someone help me Solve 6

Gala2k [10]

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3 years ago

Find the nth term of the sequence 7,25,51,85,127

olya-2409 [2.1K]

Let a (n) denote the n-th term of the given sequence.

Check the forward differences, and denote the n-th difference by b (n). That is,

b (n) = a (n + 1) - a (n)

These so-called first differences are

b (1) = a (2) - a (1) = 25 - 7 = 18

b (2) = a (3) - a (2) = 51 - 25 = 26

b (3) = a (4) - a (3) = 85 - 51 = 34

b (4) = a (5) - a (4) = 127 - 85 = 42

Now consider this sequence of differences,

18, 26, 34, 42, …

and notice that the difference between consecutive terms in this sequence b is 8:

26 - 18 = 8

34 - 26 = 8

42 - 34 = 8

and so on. This means b is an arithmetic sequence, and in particular follows the rule

b (n) = 18 + 8 (n - 1) = 8n + 10

for n ≥ 1.

So we have

a (n + 1) - a (n) = 8n + 10

or, replacing n + 1 with n,

a (n) = a (n - 1) + 8 (n - 1) + 10

a (n) = a (n - 1) + 8n + 2

We can solve for a (n) by iteratively substituting:

a (n) = [a (n - 2) + 8 (n - 1) + 2] + 8n + 2

a (n) = a (n - 2) + 8 (n + (n - 1)) + 2×2

a (n) = [a (n - 3) + 8 (n - 2) + 2] + 8 (n + (n - 1)) + 2×2

a (n) = a (n - 3) + 8 (n + (n - 1) + (n - 2)) + 3×2

and so on. The pattern should be clear; we end up with

a (n) = a (1) + 8 (n + (n - 1) + … + 3 + 2) + (n - 1)×2

The middle group is the sum,

$\displaystyle 8\sum_{k=2}^nk=8\sum_{k=1}^nk-8=\frac{8n(n+1)}2-8=4n^2+4n-8$

so that

a (n) = a (1) + (4n ² + 4n - 8) + 2 (n - 1)

a (n) = 4n ² + 6n - 3

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3 years ago

Triangle DEF, shown below, is reflected over the y-axis to form triangle D'E'F'. What are

vovikov84 [41]

Answer:

(-6, -4).

Step-by-step explanation:

When you reflect coordinates over the y-axis, the x-coordinates remain the same, but the y-coordinates become their additive inverse.

The original coordinates for F are (6, -4).

The new coordinates for F would be F' (-6, -4).

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2 years ago