Please write out the entire question so we can do our best to assist you with the most logical response.
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Answer:
Step-by-step explanation:
For this case we can define the random variable of interest as: "The nicotine content in a single cigarette " and for this case we know the following parameters:
And for this case we select a sample size of n =100 and we want to find the following probability:
And for this case we can use the z score formula given by:
And replacing we got:
And we can find the required probability with the normal standard table and we got:
Answer:
f) a[n] = -(-2)^n +2^n
g) a[n] = (1/2)((-2)^-n +2^-n)
Step-by-step explanation:
Both of these problems are solved in the same way. The characteristic equation comes from ...
a[n] -k²·a[n-2] = 0
Using a[n] = r^n, we have ...
r^n -k²r^(n-2) = 0
r^(n-2)(r² -k²) = 0
r² -k² = 0
r = ±k
a[n] = p·(-k)^n +q·k^n . . . . . . for some constants p and q
We find p and q from the initial conditions.
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f) k² = 4, so k = 2.
a[0] = 0 = p + q
a[1] = 4 = -2p +2q
Dividing the second equation by 2 and adding the first, we have ...
2 = 2q
q = 1
p = -1
The solution is a[n] = -(-2)^n +2^n.
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g) k² = 1/4, so k = 1/2.
a[0] = 1 = p + q
a[1] = 0 = -p/2 +q/2
Multiplying the first equation by 1/2 and adding the second, we get ...
1/2 = q
p = 1 -q = 1/2
Using k = 2^-1, we can write the solution as follows.
The solution is a[n] = (1/2)((-2)^-n +2^-n).
Answer:
Step-by-step explanation:
3y+7=2x
3y=2x-7
y=(2/3)x-7/3
when parallel, the y=ax+b, the a keeps the same
so it‘s y=(2/3)x-a
and it pass (2,6), so 6=(2/3)*2 -a
6=4/3-a
-a=(18-4)/3
-a=14/3
a=-14/3
The common difference is 1 1/3
40-1 1/3= 38 2/3
38 2/3-1 1/3=37 1/3
37 1/3-1 1/3=36
Therefore the missing number is 38 2/3
