Answer:
A(t) = 90e^0.12t ;
299 mg
Step-by-step explanation:
General Continous growth rate equation :
A = Pe^rt
A = amount present, t years after year of initial amount.
Here,
P = 90 mg, amount in year 2000
r = rate = 12% = 0.12
t = years after 2000
Therefore,
A is written as ;
A(t) = 90e^0.12t
Amount present in year 2010 ;
t = 2010 - 2000 = 10
A(10) = 90e^0.12(10)
A(10) = 90 * e^1.2
= 90 * 3.3201169
= 298.81052
= 299 mg
Use the formula y2-y1/x2-x1.
3-3/-4-8
0/-12
The slope is 0, so the line is horizontal.
Answer: 1.4 seconds
<u>Step-by-step explanation:</u>
The equation is: h(t) = at² + v₀t + h₀ where
- a is the acceleration (in this case it is gravity)
- v₀ is the initial velocity
- h₀ is the initial height
Given:
- a = -9.81 (if it wasn't given in your textbook, you can look it up)
- v₀ = 12
- h₀ = 3
Since we are trying to find out when it lands on the ground, h(t) = 0
EQUATION: 0 = 9.81t² + 12t + 3
Use the quadratic equation to find the x-intercepts
a=-9.81, b=12, c=3
Note: Negative time (-0.2) is not valid
Answer:
Half; twice
Step-by-step explanation:
In a circle, the radius is said to be the distance from the center of the circle to any point on the edge of the circle, it is denoted as "r". The radius is called a radii if it is more than one.. The radius of a circle is half the length of the diameter of a circle because the diameter of a circle is the distance of the line that passes through the center of a circle touching both edges of the circle. It is denoted as "d".
Thus,
2r = d
r = d/2
For example, if the radius of a circle is 10cm, the diameter of the circle will be calculated as: d = 2 * 10 = 20cm. Which means if the radius is 10cm, diameter will be 20cm.
Therefore, the radius of a circle is half the length of its diameter. the diameter of a circle is twice the length of its radius
Step-by-step explanation:
There are six trigonometric ratios, sine, cosine, tangent, cosecant, secant and cotangent. These six trigonometric ratios are abbreviated as sin, cos, tan, csc, sec, cot. These are referred to as ratios since they can be expressed in terms of the sides of a right-angled triangle for a specific angle θ.
