To answer this we need to perimeter of the room, this is 12 + 12 + 10 + 10 = 44 feet
If slope of a line is m then slope of the perpendicular line is -1/m .
so slope of perpendicular line is -3.
then use this y-y0=m(x-x0)
y+5=-3(x-2)
y+5=-3x+6
y=-3x+1
Answer: Slope: -1/2
Step-by-step explanation: To find slope take 2 points that lie on the line and use this formula to solve: <em> </em>I will use (0, -2) and (2, -3) to solve
↑ ↑ ↑ ↑
y2 - y1 x1 y1 x2 y2
-----------
x2 - x1
So, for this question, substitute the x and y values from the points above to solve.
-3 - (-2)
----------- = - 1/2
2 - 0
Hope this helped. :)
The student will have $135 in her bank account at the end of the ninth week. You can fine this out by finding out the amount she deposits a week and to do this you would take the $30 and divide it by 2 because she had $30 at the end of the second week.
30/2=15
So you see that the student deposits $15 each week, so to find out how much money she will have in 9 weeks you will multiply her $15 by 9.
15x9=135
So the student will have $135 at the end of the ninth week.
Answer:
See below
Step-by-step explanation:
(a) Field lines
A negatively charged particle has an electric field associated with it.
The field lines spread out radially from the centre of the point. They are represented by arrows pointing in the direction that a positive charge would move if it were in the field.
Opposite charges attract, so the field lines point toward the centre of the particle.
For an isolated negative particle, the field lines would look like those in Figure 1 below.
If two negative charges are near each other, as in Figure 2, the field lines still point to the centre of charge.
A positive charge approaching from the left is attracted to both charges, but it moves to the closer particle on the left.
We can make a similar statement about appositive charge approaching from the left.
Thus, there are few field lines in the region between the two particles.
(b) Coulomb's Law
The formula for Coulomb's law is
F = (kq₁q₂)/r²
It shows that the force varies inversely as the square of the distance between the charges.
Thus, the force between the charges decreases rapidly as they move further apart.