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GaryK [48]
3 years ago
13

Plssss help meeeeee plssssssss lol

Mathematics
1 answer:
Temka [501]3 years ago
3 0
Answer is A
V= 35.325in^3
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URGENT I NEED HELP RIGHT NOW 5 STAR + BRAINLY
shusha [124]
48% is very close to 50%, which is known as one-half of something. One half of 200 is 100, so 48% is about 100 (actual is 96).
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3 years ago
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The perimeter of a rectangle playground is 40 yards it is 1 1/2 yards longer than it’s Wide what is the area of the playground
Sauron [17]
Let's make W = width, and L =  length.
What do we know? We know that P = 40 yards, and L = W + 1.5 .
The formulas for perimeter and area are:
P = 2W+2L
A = W*L

We can set P to 40, and since L = W+1.5, we can substitute that in for L.
40 = 2W + 2 (W+1.5)
40 = 2W + 2W + 3
37 = 4W
W = 37/4

We can plug that into L to find the length.
L = W + 1.5
L = 37/4 + 3/2
L = 43/4

Now, we plug into the area formula!
A = L*W
A = 43/4 * 37/4
A = 1591/16 or 99.43 yd^2
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I need help quick so I can play outside
kvasek [131]

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28 POINTS SHOW WORK
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A model rocket is launched with an initial upward velocity of 100 ft/s. The rocket's height h (in feet) after t seconds is given
tamaranim1 [39]
\bf \stackrel{h}{34}=100t-16t^2\implies 16t^2-100t+34=0\\\\\\ 8t^2-50t+17=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\stackrel{\stackrel{a}{\downarrow }}{8}t^2\stackrel{\stackrel{b}{\downarrow }}{-50}t\stackrel{\stackrel{c}{\downarrow }}{+17}=0
\qquad \qquad 
t= \cfrac{ -  b \pm \sqrt {  b^2 -4 a c}}{2 a}

\bf t=\cfrac{ - (-50) \pm \sqrt {  (-50)^2 -4(8)(17)}}{2(8)}\implies t=\cfrac{50\pm \sqrt{2500-544}}{16}
\\\\\\
t=\cfrac{50\pm\sqrt{1956}}{16}\implies t=\cfrac{50\pm\sqrt{4\cdot 489}}{16}\implies t=\cfrac{50\pm\sqrt{2^2\cdot 489}}{16}
\\\\\\
t=\cfrac{50\pm 2\sqrt{489}}{16}\implies t=\cfrac{25\pm \sqrt{489}}{8}\implies t\approx
\begin{cases}
5.88916805\\
0.36083195
\end{cases}
4 0
3 years ago
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