Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
Answer:
2
Step-by-step explanation:
You would replace the x with -2x so you would end up with -2×-2 and that is 4 then minus 2 is 2.
I say B it intercepts both axis
Answer:
yes
Step-by-step explanation:
Answer:
Step-by-step explanation:
Simplify to get 
Find what 
equals to by taking away 8, 
.
Divide by 2 to find x, 
