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2 years ago

Lexi say that -68 feet is a greater depth than- 75 feet, since-68>-75. Is Lexi correct? Explain

Mathematics

1 answer:

lara [203]2 years ago

7 0

Answer:

Step-by-step explanation:

When working with negative numbers in terms of depth, greater depth are depicted by values as we move farther to the left of the number line.

With this in mind, - 75 feets is farther to the left of the number line and as such represents a greater depth value Than - 68 feets

Therefore, when expressing depth or elevation distances, the values should be iewwd in absolute terms. Then |75| > |68|. While bearing in mind that depth is downward and thus negative

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Given a slope and a point write a perpendicular equation in standard form.

jeyben [28]

Hi there! The answer would be:

y=-2/5x+2.

Explanation:
We can start by plotting the given point (-5,3). From there, we can use the slope to place other points to find the y intercept. Using the slope of the graph, we can find that the line segment hits (2,0). Therefore, how answer would be: y=-2/5x+2

Hope this helps!!! :DD
mark brainliest if possible! If not, that’s okay!

5 0

2 years ago

_________________<br>√(-√2-(-√2))²+(√3-2√3)²

xz_007 [3.2K]

_________________
√(-√2-(-√2))²+(√3-2√3)²= 3

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2 years ago

Assuming that the equations define x and y implicitly as differentiable functions x=f(t),y=g(t) find the slope of the curve x=f(

Mumz [18]

The given equations are
$x(t+1)-4t \sqrt{x} =9$ (1)
$2y+4y^{3/2}=t^{3}+t$ (2)

When t=0, obtain
$x=9 \\ 2y+4y^{3/2}=0 \,\,=\ \textgreater \ \, y(1+2 \sqrt{y} )=0 \,=\ \textgreater \ \,y=0$

Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
When t=0, obtain
x'(0) + x(0) - 4√x(0) = 0
x'(0) + 9 - 4*3 = 0
x'(0) = 3
Here, x' means $\frac{dx}{dt}$ .

Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
When t=0, obtain
2y'(0) +6√y(0) * y'(0) = 1
2y'(0) = 1
y'(0) = 1/2.
Here, y' means $\frac{dy}{dt}$ .

Because $\frac{dy}{dx} = \frac{dy}{dt} / \frac{dx}{dt}$ , obtain
$\frac{dy}{dx} |_{t=0}\, = \frac{1/2}{3}= \frac{1}{6}$

Answer:
The slope of the curve at t=0 is 1/6.

3 0

2 years ago

-3/7, -8/3 and -5/2,-2 slope

Alja [10]

So the points are (-3/7,-8/3) and (-5/2,-2)
to find the slope do
(y2-y1)/(x2-x1)
(x,y)
x1=-3/7
y1=-8/3
x2=-5/2
y2=-2

subsitute
$\frac{-2-( \frac{-8}{3} )}{ \frac{-5}{2} - \frac{-3}{7} }$
simplify by finding similar denomenators
$\frac{\frac{-6}{3}-( \frac{-8}{3} )}{ \frac{-35}{14} - \frac{-6}{14} }$
$\frac{\frac{-6}{3}( \frac{8}{3} )}{ \frac{-35}{14} + \frac{6}{14} }$
add
$\frac{\frac{2}{3}}{ \frac{-29}{14}}$
multiply top and bottom by $\frac{-14}{29$
$\frac{\frac{-28}{87}}{1}$
$\frac{-28}{87}$
answer is
slope= $\frac{-28}{87}$

8 0

2 years ago

Fill out the chart please!

jarptica [38.1K]

1. Mean of the data: 8

2. Median: 8

3. IQR = 4

4. Members that use the facility 10 days a month is: 2.

See reasons below.

<h3>What is the Mean, Median, and Interquartile Range of a Data?</h3>

Mean = sum of all values ÷ number of data values (easily solved using a dot plot

Median = middle value (easily found using a box plot).

Interquartile range (IQR) = Q3 - Q1 (easily found using a box plot).

1. Mean of the data: use the dot plot.

Reasoning: (3 + 3 + 5 + 6 + 6 + 7 + 8 + 8 + 8 + 9 + 10 + 10 + 11 + 12 + 14)/15 = 8

2. Median of the data set: Using the box plot, it is the value indicated by the vertical line that divides the box.

Median = 8

3. IQR = Q3 - Q1 = 10 - 6

IQR = 4

4. Members that use the facility 10 days a month, using the dot plot is: 2. 10 has 2 dots.

Learn more about the mean, median, and interquartile range on:

brainly.com/question/9821103

#SPJ1

4 0

1 year ago