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Goryan [66]
3 years ago
5

Pls someone help me find the answers

Mathematics
1 answer:
Alecsey [184]3 years ago
7 0

Answer:

x = 145°

Step-by-step explanation:

We know that y = 98°, so we can find ∠DBC:

180°-y = ∠DBC

180°-98° = 82°

We also know that z = 63°, therefore we can apply <u>exterior angle of triangles</u> to find x.

∠DBC + z = x

82°+63° = x

x = 145°

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Is y=x2-1 a linear equation
Inga [223]
Y=x2-1 is not a linear equation only because for it to be an linear equation it would have to be 2x-1=y or y=2x-1
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3 years ago
A rope which is 10.3 centimeters long is cut into 4 pieces of equal length. Write an equation to find the length of
alexdok [17]

Answer: x = 10.3 ÷ 4

Step-by-step explanation: if we were to work this out forgetting about the equation it can be worked out by dividing the 10.3 by 4 to find the length of the pieces so, now to express it as an equation, we have to add x into our sum 4 × ? = 10.3 : 4x = 10.3. The answer for x would be x = 2.58.

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Read 2 more answers
Simplify"<br>2x² + 16x + 14 / X² - 1​
Phoenix [80]

Answer:  16x+3+x214​

Step-by-step explanation:

Multiply 2 and 2 to get 4.

4+16x+x214​−1

Subtract 1 from 4 to get 3.

3+16x+x214​

To add or subtract expressions, expand them to make their denominators the same. Multiply 3+16x times x2x2​.

x2(3+16x)x2​+x214​

Since x2(3+16x)x2​ and x214​ have the same denominator, add them by adding their numerators.

x2(3+16x)x2+14​

Do the multiplications in (3+16x)x2+14.

x23x2+16x3+14​

5 0
3 years ago
Which statement is true about the polynomial 3j4k−2jk3+jk3−2j4k+jk3 after it has been fully simplified?
tamaranim1 [39]

Answer:

j^4k

Step-by-step explanation:

3j^4k-2jk^3+jk^3-2j^4k+jk^2\\2j^4k-2j^4k-2jk^3+jk^3+jk^3\\j^4k

3 0
3 years ago
Ah! Okay, need help solving 14, and just checking for 16 and 4.
Allisa [31]
4. Correct. You also could have used the limit test for divergence for the same conclusion (the summand approaches infinity).

- - -

14. I'm guessing the instructions are the same as for 16. Rewrite as

f(x)=\dfrac4{2x+3}=\dfrac{\frac43}{1-\left(-\frac{2x}3\right)}

Now recall that for |x|, we have

\dfrac1{1-x}=\displaystyle\sum_{n\ge0}x^n

so that for this function, we get

f(x)=\dfrac43\displaystyle\sum_{n\ge0}\left(-\frac{2x}3\right)^n

Because this is a geometric sum, this converges when \left|-\dfrac{2x}3\right|, or |x|. This would be the interval of convergence.

Your hunch about checking the endpoints is correct. Checking is easy in this case, because at the endpoints (-3/2 and 3/2) the series obviously diverges.

- - -

16. This one is kind of tricky, and there's more than one way to do it. The standard method would be to take the antiderivative:

F(x)=\displaystyle\int f(x)\,\mathrm dx=\int\frac{\mathrm dx}{(1+x)^2}=-\frac1{1+x}+C

We also have

\displaystyle-\frac1{1+x}=-\frac1{1-(-x)}=-\sum_{n\ge0}(-x)^n\implies F(x)=C-1-\sum_{n\ge1}(-x)^n

and differentiating this gives

f(x)=-\displaystyle\sum_{n\ge1}n(-x)^{n-1}=-\sum_{n\ge0}(n+1)(-x)^n=\sum_{n\ge0}(n+1)(-1)^{n+1}x^n

By the ratio test, this converges when

\displaystyle\lim_{n\to\infty}\left|\frac{(n+2)(-1)^{n+2}x^{n+1}}{(n+1)(-1)^{n+1}x^n}\right|

The limit reduces to

\displaystyle|x|\lim_{n\to\infty}\frac{n+2}{n+1}=|x|

and so the series converges absolutely for |x|. Checking the endpoints is also easy in this case. The factor of n+1 is a clear sign that the series will diverge at either extreme.
7 0
3 years ago
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