Answer:
<em>(D). (3, 1) </em>
Step-by-step explanation:
y ≤ 3x - 4
<u><em>(A). (0, 4)</em></u>
4 ≤ 3(0) - 4
4 ≤ - 4 <u><em>(False statement)</em></u>
<u><em>(B). (-2, 0)</em></u>
0 ≤ 3(- 2) - 4
0 ≤ - 10 <u><em>(False statement) </em></u>
<u><em>(C). (0, 0)</em></u>
0 ≤ 3(0) - 4
0 ≤ - 4 <u><em>(False statement)</em></u>
<u><em>(D). (3, 1)</em></u>
1 ≤ 3(3) - 4
1 ≤ 5 <u><em>(True statement) </em></u>
The second one they do not have to pass trough (0,0)
Number two is quadrant 3 if you look up quadrants on a graph it will show you where each quadrant is. You can use this website symbolab for number 3.
You can use Desmosgraphing for number 4
Answer:
Yes
Step-by-step explanation:
Because its the square root of 12