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irina1246 [14]
3 years ago
15

Need help pls answer fast

Mathematics
2 answers:
enot [183]3 years ago
7 0

Answer:

1:2

Step-by-step explanation:

babunello [35]3 years ago
4 0

Answer:the last question is 50%

Step-by-step explanation:

i hope you understand

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Write a Let" statement for the unknown, write an equation, and solve the equation. 11. Jane bought a number of records for $7 ea
Advocard [28]

Let n = number of records.

Each record costs $7, so n records cost 7n.

She then spent $3, so the total spent is 3n + 3.

She spent a total of $24, so 3n + 3 must equal 24. That gives us the following equation.

7n + 3 = 24

Subtract 3 from both sides.

7n = 21

Divide both sides by 7.

n = 3

Answer: She bought 3 records.

3 0
3 years ago
Ratio between 80% and 20%
musickatia [10]
4:1 is the answer............
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The area of a trapezium is 384cm². Its parallel sides are in the ratio3 : 5 and the perpendicular distance between them is 12 cm
Pani-rosa [81]
Area of trapezium=384 square cm
Ratio of parallel sides=
Distance between parallel sides=h=12 cm
5 0
3 years ago
The elevations of four locations are shown in the table
nevsk [136]

Answer:

c. new Orleans is closer to sea level than salton trough.

Step-by-step explanation:

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5 0
2 years ago
Read 2 more answers
A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.
noname [10]

Answer:

Width = 4ft

Height = 4ft

Length = 8ft

Step-by-step explanation:

Given

Volume = 128ft^3

L = 2W

Base\ Cost = \$9/ft^2

Sides\ Cost = \$6/ft^2

Required

The dimension that minimizes the cost

The volume is:

Volume = LWH

This gives:

128 = LWH

Substitute L = 2W

128 = 2W * WH

128 = 2W^2H

Make H the subject

H = \frac{128}{2W^2}

H = \frac{64}{W^2}

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

A = LW + 2(WH + LH)

The cost is:

Cost = 9 * LW + 6 * 2(WH + LH)

Cost = 9 * LW + 12(WH + LH)

Cost = 9 * LW + 12H(W + L)

Substitute: H = \frac{64}{W^2} and L = 2W

Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)

Cost =18W^2 +  \frac{768}{W^2}*3W

Cost =18W^2 +  \frac{2304}{W}

To minimize the cost, we differentiate

C' =2*18W +  -1 * 2304W^{-2}

Then set to 0

2*18W +  -1 * 2304W^{-2} =0

36W - 2304W^{-2} =0

Rewrite as:

36W = 2304W^{-2}

Divide both sides by W

36 = 2304W^{-3}

Rewrite as:

36 = \frac{2304}{W^3}

Solve for W^3

W^3 = \frac{2304}{36}

W^3 = 64

Take cube roots

W = 4

Recall that:

L = 2W

L = 2 * 4

L = 8

H = \frac{64}{W^2}

H = \frac{64}{4^2}

H = \frac{64}{16}

H = 4

Hence, the dimension that minimizes the cost is:

Width = 4ft

Height = 4ft

Length = 8ft

8 0
2 years ago
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