Consider a nuclear power plant that produces 1200 MW of power and has a conversion efficiency of 34 percent (that is, for each u
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Answer:
The quantity of large frames is 7
The quantity of small frames is 13
Step-by-step explanation:
Given as :
The price of each large frames = $ 10
The price of each small frames = $ 5
The total number of both frames bought = 20
The price for both the frames = $ 135
Now,
Let the quantity of large frames = L
And The quantity of small frames = S
So , According to question
The total number of both frames bought = 20
Or, The quantity of large frames + the quantity of small frame = 135
Or, L + S = 20 ......A
And $ 10 L + $ 5 S = $ 135 ................B
Or, $ 10× ( L + S ) = $ 10× 20
Or, $ 10 L + $ 10 S = $ 200
( $ 10 L + $ 10 S ) - ( $ 10 L + $ 5 S ) = $ 200 - $ 135
Or , ( $ 10 L - $ 10 L ) + ( $ 10 S - $ 5 S ) = $ 65
Or, 0 + 5 S = 65
∴ S =
I.e S = 13
So, The quantity of small frames = S = 13
Put the Value of S in eq A
So , L + S = 20
Or, L = 20 - S
Or, L = 20 - 13
∴ L = 7
So, The quantity of large frames = L = 7
Hence The quantity of large frames is 7
And The quantity of small frames is 13 Answer