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AlekseyPX
3 years ago
10

**MARKING BRAINLIEST PLEASE HELP**

Mathematics
1 answer:
raketka [301]3 years ago
3 0

Answer:

\text{1. } v=16t+\frac{h-c}{t},\\\text{2. }90\:\mathrm{ft/s}, \\\text{3. Cannot be determined}

Step-by-step explanation:

1. The initial equation given to us is h=-16t^2+vt+c. Rearranging the equation to isolate v, we have:

vt=16t^2+h-c,\\\boxed{v=16t+\frac{h-c}{t}}

2. Using the equation we rearranged in part 1, we can substitute given values:

v=16(3)+\frac{131-5}{3},\\v=48+42=\boxed{90\:\mathrm{ft/s}}

3. We see from our equation in part 1 (v=16t+\frac{h-c}{t}) that when t=0, the denominator of our fraction will be equal to 0. Since we cannot divide by 0, the velocity remains undefined and cannot be determined.

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I need to step-by- step ways on how this is or isn’t a solvable equation. Please HELP
Darya [45]

Answer:

it is a solvable equation

Step-by-step explanation:

(x + 2) -3(x - 4) = 6 and x = 4

if x = 4 then fill in all the x's with 4 so the equation is now:

(4 + 2) -3(4 - 4) = 6

Use PEMDAS

Now the equation is 6 - 3(0) = 6

-3 times 0 is 0 so it's 6-0=6

6 = 6

when you put the 4 in for the x variables and the numbers on both sides of the equal sign are the same it makes the equation true

hope this makes sense and hope it helps :)

3 0
3 years ago
PLEASE HELP!! I can't figure this out
9966 [12]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Three circles with centers A, B, and C are externally tangent to each other as shown in the figure. Lines EG and DG are tangent
fiasKO [112]
My solution to the problem is as follows:

EC = 15 ... draw CF = 6 (radius) ...use Pythagorean theorem to find EF. 

EF^2 + CF^2 = EC^2 
EF^2 = 15^2 - 6^2 = 189 .... EF = sq root 189 

triangle GDE is similar to CFE ... thus proportional 
GD / ED = CF / EF 
GD / 18 = 6 / (sq root 189) 
<span>GD = 108 / (sq root 189)

I hope my answer has come to your help. God bless and have a nice day ahead!


</span>
5 0
3 years ago
Help me please, i just need an answer
Kruka [31]

Answer:

6

Step-by-step explanation:

4 0
3 years ago
A distributor of personal computers has five locations in a city. In the year's first quarter, the sales in units were: Location
Deffense [45]

Answer:

The correct option is (c) 13.277.

Step-by-step explanation:

The observed data is:

Location                      Observed sales (units)

Northside                                70

Pleasant Township                 75

Southwick                               70

I-90                                          50

Venice Avenue                       35

TOTAL                                   300

The test statistic for the Goodness of fit test is:

\chi^{2}=\sum\frac{(Observed-Expected)^{2}}{Expected}

For <em>k</em> independent samples this test statistic follows a Chi-square distribution with degrees of freedom (<em>k</em> - 1).

The sample size in this case is, <em>k</em> = 5.

The degrees of freedom is, (<em>k</em> - 1) = 4.

The level of significance is, <em>α</em> = 0.01.

The critical value of the test is:

\chi^{2}_{\alpha ,k-1}=\chi^{2}_{0.01,4}=13.277

**Use the Chi-square table.

Thus, the critical value is 13.277.

7 0
3 years ago
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