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AlekseyPX
3 years ago
10

**MARKING BRAINLIEST PLEASE HELP**

Mathematics
1 answer:
raketka [301]3 years ago
3 0

Answer:

\text{1. } v=16t+\frac{h-c}{t},\\\text{2. }90\:\mathrm{ft/s}, \\\text{3. Cannot be determined}

Step-by-step explanation:

1. The initial equation given to us is h=-16t^2+vt+c. Rearranging the equation to isolate v, we have:

vt=16t^2+h-c,\\\boxed{v=16t+\frac{h-c}{t}}

2. Using the equation we rearranged in part 1, we can substitute given values:

v=16(3)+\frac{131-5}{3},\\v=48+42=\boxed{90\:\mathrm{ft/s}}

3. We see from our equation in part 1 (v=16t+\frac{h-c}{t}) that when t=0, the denominator of our fraction will be equal to 0. Since we cannot divide by 0, the velocity remains undefined and cannot be determined.

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alexandr1967 [171]

Answer:

43.66

Step-by-step explanation:

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3 years ago
Write the quadratic equation whose roots are -3 and 2 , and whose leading coefficient is 5
KiRa [710]

Step-by-step explanation:

Since, roots are - 3 & 2

Therefore, (x + 3) & (x - 2) would be factors.

Leading coefficient is 5

Hence, required quadratic equation is:

5(x + 3)(x - 2) = 0 \\   \therefore \:  5( {x}^{2}  - 2x + 3x - 6)  = 0\\  \therefore \:  5( {x}^{2}  + x - 6)  = 0\\ \therefore \: 5 {x}^{2}  + 5x - 30  = 0\:  \\ is \: the \: required \:   quadratic \: equation.

5 0
3 years ago
3 erasers cost $4.41. Write a proportion that would solve for the cost of 4 erasers.
Bess [88]

Answer:

$5.88

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3 erasers ⇒ $4,41

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7 0
2 years ago
Read 2 more answers
Wanda placed $100 in a savings account that pays 2% simple interest per year. After 6 months Wanda made another deposit of $100.
STatiana [176]

Answer:

\$203.01

Step-by-step explanation:

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

<em>After 6 months</em>

t=6/12=0.5\ years\\ P=\$100\\r=2\%=2/100=0.02

substitute in the formula above

A_1=100(1+0.02*0.5)

A_1=100(1.01)

A_1=\$101

<em>At the end of one year</em>

t=6/12=0.5\ years\\ P=A_1+\$100=\$101+\$100=\$201\\r=2\%=2/100=0.02

substitute in the formula above

A_2=201(1+0.02*0.5)

A_2=201(1.01)

A_2=\$203.01

8 0
4 years ago
Find (1/3 + 5/6 - 1/6) / (4/5)<br>​
Marta_Voda [28]

Answer:

\frac{5}{4}

Step-by-step explanation:

(\frac{1}{3} + \frac{5}{6} - \frac{1}{6}) \div \frac{4}{5}\\\\( \frac{2 + 5 - 1}{6}) \div \frac{4}{5} \\\\(\frac{6}{6}) \div \frac{4}{5}\\\\\frac{1}{\frac{4}{5}}\\\\\frac{5}{4}

5 0
3 years ago
Read 2 more answers
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