Perimeter=54 a.2ft b.9 missing length=4 a.light rectangle=15 dark rectangle=10 b. sum=25 5*5=25
Answer:
Simplifying
3x + 77 = 4x + 54
Reorder the terms:
77 + 3x = 4x + 54
Reorder the terms:
77 + 3x = 54 + 4x
Solving
77 + 3x = 54 + 4x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-4x' to each side of the equation.
77 + 3x + -4x = 54 + 4x + -4x
Combine like terms: 3x + -4x = -1x
77 + -1x = 54 + 4x + -4x
Combine like terms: 4x + -4x = 0
77 + -1x = 54 + 0
77 + -1x = 54
Add '-77' to each side of the equation.
77 + -77 + -1x = 54 + -77
Combine like terms: 77 + -77 = 0
0 + -1x = 54 + -77
-1x = 54 + -77
Combine like terms: 54 + -77 = -23
-1x = -23
Divide each side by '-1'.
x = 23
Simplifying
x = 23
Step-by-step explanation:
I hope its helps
Answer:
The figure is NOT unique.
Imagine the following quadrilaterals:
Rectangle
Square
We know that:
Both quadrilaterals have at least two right angles.
However, they are not unique because they depend on the lengths of their sides.
Step-by-step explanation:
To construct a quadrilateral uniquely, five measurements are required. A quadrilateral can be constructed uniquely if the lengths of its four sides and a diagonal are given or if the lengths of its three sides and two diagonals are given.
Just given two angles we cannot construct a unique quadrilateral. There may be an infinite number of quadrilaterals having atleast two right angles
Examples:
All squares with varying sides
All trapezoids with two right angles
All rectangles with different dimensions
and so on.
Answer is
No.
Answer:
2 animals
Step-by-step explanation:
Number of animals=40
Fraction of fish=3/4
=>number of fish=3/4*40=30
Fraction of cats=1/5
=>number of cats=1/5*40=8
Animals which are not cats or fish are=total number of animals-(number of cats + number of fish)
Animals which are not cats or fish=40-(8+30)
40-38
2 animals
Where’d the rest of the question?
