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romanna [79]
3 years ago
14

helpppppppp pls answer only if you know where to put them, PLEASEEE DO NOT ANSWER FOR THE POINTS I'VE ASKED THIS QUESTION LIKE A

LOT OF TIMES ALREADY AND ALL OF Y'ALL ONLY ANSWER FOR POINTS!!!!!!!!!! COULD YOU PLEASE NUMBER WHERE EACH ONE GOES LIKE THE ONES THAT ARE IN RED IN THE CORNER, LET ME KNOW WHERE TO PUT THEM JUST NUMBER THEM

Chemistry
1 answer:
chubhunter [2.5K]3 years ago
7 0

Answer:

Explanation: i hope this helped

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For the reaction N2(g) + O2(g)2NO(g) H° = 181 kJ and S° = 24.9 J/K G° would be negative at temperatures (above, below) K. Enter
12345 [234]

ΔG deg will be negative above 7.27e+3 K.

<u>Explanation:</u>

  • The ΔG deg with the temperature can be found using the formula and the formula is given below
  • ΔG deg = ΔH deg - T ΔS deg
  • Given data, ΔH deg = 181kJ and ΔSdeg=24.9J/K
  • -T ΔS deg will be always negative and ΔG deg = ΔH deg  will  be  positive and ΔG deg will be negative at relatively high temperatures and positive at relatively low temperatures
  • solving the equation and substitute  ΔGdeg=0
  • ΔGdeg = ΔHdeg - T ΔSdeg
  • T= ΔHdeg/ΔSdeg
  • T=181 kJ / 2.49e-2 kJK-1
  • By simplification we get
  • T=7.27 × 10^3 K.
  • Therefore, Go will be negative above   7.27 × 10^3 K
  • Since ΔG deg = -RT lnK, when ΔGdeg < 0, K > 1 so the reaction will have K > 1 above 7.27 × 10^3 K.
  • ΔG deg will be negative above 7.27e+3 K.

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7 0
3 years ago
Can you please me with this​
dalvyx [7]
The first answer choice would be more conservative to our environment
5 0
3 years ago
Read 2 more answers
as a gas occupied a volume of 250cc at 250at 700mm pressure temperature,25degree Celsius what additional pressure is required?re
Allisa [31]

Additional pressure required : 175 mm

<h3>Further explanation</h3>

Boyle's Law  

At a constant temperature, the gas volume is inversely proportional to the pressure applied  

\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}

V₁=250 ml

P₁=700 mmHg

\tt V_2=\dfrac{4}{5}\times 250=200~ml

\tt P_2=\dfrac{P_1.V_1}{V_2}\\\\P_2=\dfrac{700\times 250}{200}=875~mmHg

Additional pressure :

\tt 875-700=175~mm

4 0
3 years ago
Which statement is an identifying characteristic of a mixture?
castortr0y [4]
A mixture<span> is the blending of two or more dissimilar substances. A major </span>characteristic<span> of </span>mixtures<span> is that the materials do not chemically combine. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
8 0
4 years ago
The first-order isomerization reaction: cyclopropane → propene has a rate constant of 1.10×10-4 s-1 at 470°C and 5.70×10-4 s-1 a
BigorU [14]

Answer:

Activation energy, Ea, for the reaction 261.7 kj/mole

Explanation:

Given

Rate constant at 470 ⁰C (K₁) = 1.10 x 10⁻⁴ s⁻¹ and rate constant at 500⁰C (K₂) = 5.7 x 10⁻⁴ s⁻¹

Temperature (T₁) = 470 + 273 = 743 K and

temperature (T₂) = 500 + 273 = 773 K

Activation energy (Eₐ) = ?

Universal gas constant (R) = 8.314 J. K⁻¹. mole⁻¹

We know   log\frac{K_{2} }{K_{1} } = \frac{E_{a} }{2.303XR}\frac{(T_{2}-T_{1} ) }{T_{2}T_{1}  }

              ⇒ log \frac{5.7 X 10^{-4} }{1.1 X 10^{-4} } = \frac{E_{a} }{2.303X8.314} \frac{(773 - 743)}{773X743}

              ⇒ 0.714 = \frac{E_{a}X30 }{10996950.3}

              ⇒ Eₐ = \frac{7851822.5}{30} j/mole = 261.7 Kj/mole

5 0
3 years ago
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