2 years ago

Please help me with number 4 and 5 on my study guide

Chemistry

1 answer:

Shtirlitz [24]2 years ago

5 0

Answer:

help with problem 4

Explanation:

4. protons are equal to atomic numbers. neutrons are atomic mass minus atomic number. electrons are equal to protons.

5. I don't know, sorry.

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A process called fission which generates heat to produce steam, which is used by a turbine generator to generate electricity.

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3 years ago

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If 27 ml of 6.0 m h2so4 was spilled, what is the minimum mass of nahco3 that must be added to the spill to neutralize the acid?

katrin [286]

The minimum mass of NaHCO3 that must be added to the spill to neutralize the acid is 27.216 grams

<h3>calculation </h3>

write the balanced chemical equation

2NaHCO3 +H2SO4 → Na2SO4 +2H2O +2CO2

find the moles of H2SO4 = molarity x volume in liters

volume in liters = 27/1000=0.027 l

moles is therefore= 0.027 x6=0.162 moles

by use of mole ratio of NaHCO3: H2SO4 which is 2:1 the moles of NaHCO3=0.162 x2=0.324 moles

mass of NaHCO3= moles of NaHCO3 x molar mass of NaHCO3(84g/mol)

= 84g/mol x 0.324=27.216 grams

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4 years ago

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3 years ago

At a certain temperature a 42.55% (v/v) solution of ethyl alcohol, C2H5OH, in water has a density of 0.9027 g mL-1. The density

swat32

Answer:

a. 7.187M.

b. 7.962m.

c. 0.1846

Explanation:

This solution contains 42.55mL of ethyl alcohol in 100mL of solution.

a. Molar concentration = Moles ethyl alcohol / L solution:

Moles ethyl alcohol -Molar mass: 46.07g/mol-

42.55mL * (0.7782g/mL) * (1mol / 46.07g) = 0.7187 moles ethyl alcohol

Liters solution:

100mL * (1L / 100mL) = 0.100L

Molar concentration: 0.7187mol / 0.100L = 7.187M

b. Molal concentration: Moles ethyl alcohol (0.7187moles) / kg solution

kg solution:

100mL * (0.9027g / mL) * (1kg / 1000g) = 0.09027kg

Molal concentration: 0.7187mol / 0.09027kg = 7.962m

c. Mole fraction: Moles ethyl alcohol / Moles ethyl alcohol + moles water

Moles water: -molar mass: 18.01g/mol-

Volume water = 100mL - 42.55mL = 57.45mL

57.45mL * (0.9949g/mL) * (1mol/18.01g) = 3.1736 moles water

Moles fraction:

0.7187 moles ethyl alcohol / 0.7187 moles ethyl alcohol+3.1736 moles water

= 0.1846

4 0

3 years ago