To calculate the relative vector of B we have to:
![P_B=\left[\begin{array}{ccc}3\\3\\-2\\3/2\end{array}\right]](https://tex.z-dn.net/?f=P_B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%5C%5C3%5C%5C-2%5C%5C3%2F2%5Cend%7Barray%7D%5Cright%5D)
The coordenates of:
, with respect to B satisfy:
Equating coefficients of like powers of t produces the system of equation:
After solving this system, we have to:
And the result is:
Learn more: brainly.com/question/16850761
The slope is rise over run, how many times you go up (or if down it'd be a negative) and over.
The y-intercept is what point on the y axis the line passes through
Answer:
Step-by-step explanation:
2p - q + 4 - ( p - q )
2p - q + 4 - p + q
By rearranging the terms
2p - p + 4
( you might think where -q and +q went ???
They are cancelled because they have opposite signs )
∴The answer is p + 4
Hope it helps
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Answer:
8 seconds.
Step-by-step explanation:
To solve this question, we need to find the time, 
, when 
, that is, when the height of the object above the ground is 0 feet.
Substituting 
feet per second and gives the quadratic:
Since 128 is divisible by 16, it can be reduced to 
.
We must now solve for .
We can easily see that one answer to the equation is 0,
(we need not concern ourselves with the 16 outside of the parenthesis as in the equation above, since 16 multiplied by 0 is 0). However this is the time the object is released into the air.
The second answer, 
is also easy to see by inspection:
.
Therefore the object lands 8 seconds after it is thrown.
