£5.00 is the answer I think so at least. I am not very good at maths but this is what I got
-35, 30, -25, -20 is that right?
<span>ax^2+bx+c
x^2-4x+3
(x-3)(x-1)=0
x=3, x=1 when y=0
The graph of the parabola has a minimum because a is positive.
(3+1)/2=2 so y will be at a minimum when x=2
f(x)=y=2^2-(4*2)+3
=4-8+3</span>
Answer:
<h2>
A. 1/6^2</h2>
Step-by-step explanation:
6^3/6^6 = 1/216
1/6^2 = 1/36 ≠ 1/216
1/6^3 = 1/216
