point G is rotated 90°. the coordinate of the pre-image G was (7,-5), and it’s image G’ is at the coordinate (5,7). What is the
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The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9
<h3>How to determine the quadratic equation?</h3>From the question, the given parameters are:
Roots = (-1 - √2)/3 and (-1 + √2)/3
The quadratic equation is then calculated as
f(x) = The products of (x - roots)
Substitute the known values in the above equation
So, we have the following equation
This gives
Evaluate the products
Evaluate the like terms
So, we have
f(x) = x²+ 2/3x - 1/9
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