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LenaWriter [7]
2 years ago
12

YO SMART PEOPLE WHO CAN 100% ANSWER CORRECTLY ONLY!!!!!!!!!!!! FAILING MATH NEED URGENT HELP!!!!!!!!!! INEQUALITIES!!!! Answer n

umber 10

Mathematics
2 answers:
ziro4ka [17]2 years ago
8 0
Look up photomath in the app store works good
dexar [7]2 years ago
5 0
C x > 3/4

okay? hope this helps
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Step-by-step explanation:


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What is the equation of the line that best fits the given data?
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Which is a function?<br> look at pic
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Answer:

option 2 {(12, 3), (11,2), ...}

Step-by-step explanation:

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8 0
2 years ago
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Answer:

y = 3(2)^x

Step-by-step explanation:

Given

The attached table

Required

Determine the exponential function

An exponential function is represented as:

y = ab^x

From the table;

(x,y)=(0,3)

So:

y = ab^x

3 = a * b^0

3 = a * 1

3 = a

a = 3

Also:

(x,y) = (1,6)

So:

y = ab^x

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6 = a * b

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3 0
3 years ago
According to a study conducted in one city, 39% of adults in the city have credit card debts of more than $2000. A simple random
Butoxors [25]

Answer:

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean \mu = 0.39 and standard deviation s = 0.0488

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

p = 0.39, n = 100

Then

s = \sqrt{\frac{0.39*0.61}{100}} = 0.0488

By the Central Limit Theorem:

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean \mu = 0.39 and standard deviation s = 0.0488

5 0
2 years ago
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