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slava [35]
3 years ago
11

Which answer goes in what box

Mathematics
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

(2,6) and (-2,6) is in the second box

(8,-2) and (8,2) is in the first box

(-5,7) and (-5,-7) is in the first box

(-3,-3) and (3,-3) is in the second box

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I can create and use a graph to predict values and justify my results? Help me with this please I would appreciate it
mestny [16]

Answer:

simple even tho im in 6th grade it would be over $100

5 0
3 years ago
Find the unknown side length
Westkost [7]
For any right triangle, we can use the Pythagorean Theorem. The Pythagorean Theorem states that for any right triangle, the legs when squared and added together will be equal to the hypotenuse squared.

In mathematical notation: a^2 + b^2 = c^2

Where the variables a and b are the legs and the variable c is the hypotenuse.

Because we know the two side lengths of the triangle, we can solve for the unknown side.

We know the length of one of the legs and the hypotenuse.

Plug in the values.

10^2 + b^2 = 24^2 \\ \\ 
100 + b^2 = 576 \\ \\ 
b^2 = 476 \\ \\ 


b = \sqrt{476}

So, the square root of 476 is the unknown length.
3 0
3 years ago
the length of a rectangle exceeds its width by 17 inches, and the area is 18 square inches. what are the length and width of the
dimaraw [331]

The length and width of the rectangle are 18 in and 1 in, respectively.

<h3>Quadrilaterals</h3>

There are different types of quadrilaterals, for example, square, rectangle, rhombus, trapezoid, and parallelogram.  Each type is defined accordingly to its length of sides and angles. For example, in a rectangle,  the opposite sides are equal and parallel and their interior angles are equal to 90°.

The area of a rectangle can be found for the formula : b*h, where b = base and h =height.

For this question, the length exceeds its width by 17 inches - L=W+17. Here, the length is the base and the width is the height. Thus,  from the value of area given, you can find the values of the length and width of the rectangle.

A=b*h

18=(W+17)*W

18=W²+17W

W²+17W-18=0

Solving this quadratic equation, you have:

w_{1,\:2}=\frac{-17\pm \sqrt{17^2-4\cdot \:1\cdot \left(-18\right)}}{2\cdot \:1}

w_{1,\:2}=\frac{-17\pm \:19}{2\cdot \:1}

w1=1 and w2= -18

For dimensions, only positive numbers must be used. Then, the width is equal to 1 inch.

As, the area (l*w) is 18 in², see.

18=l*w

18=l*1

l=18 in

Read more about the area of rectangle here:

brainly.com/question/25292087

#SPJ1

5 0
2 years ago
PLEASE HELP - System of equations matrix prepresents
Sever21 [200]

9514 1404 393

Answer:

  the marked choice is the correct one

Step-by-step explanation:

A suitable calculator or web app can reduce this matrix for you.

The solution is represented by the matrix ...

  \left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-1\\0&0&1&3\end{array}\right]

6 0
3 years ago
What is the diameter of a circle that has an area of 49pie
tester [92]
There would not be one
6 0
3 years ago
Read 2 more answers
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