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2 years ago

Help me with this question please

Mathematics

1 answer:

docker41 [41]2 years ago

6 0

7x/x-4 * x/x+7

mutiply the numerators together

(7x)(x)= 7x^ 2

mutiply the denominators together

(x-4)(x+7)

(x)(x)(7)(x)= x^2+7x

(-4)(x)(-4)(7)= -4x-28

x^2+7x-4x-28

x^2+3x-28

Answer:

7x^2/x^ 2+3x-28

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See the denomenators

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Drag the values to order them from least to greatest, with the least at the top. Item 2 moved to position 3. 79 − − √ + 63 − − √

Nonamiya [84]

$\sqrt{63} \\ \\ \sqrt{79} \\ \\ \sqrt{143} \\ \\ 4\pi$

<h2>Explanation:</h2>

As I understand, in this exercise, we have the following numbers:

$\text{Number 1}=\sqrt{79} \\ \\ \text{Number 2}=\sqrt{63} \\ \\ \text{Number 3}=\sqrt{143} \\ \\ \text{Number 4}=4\pi$

By using calculator, let's convert those numbers into decimal form:

$\text{Number 1} \approx 8.88\\ \\ \text{Number 2} \approx 7.93 \\ \\ \text{Number 3} \approx 11.96 \\ \\ \text{Number 4} \approx 12.56$

So arranging from least to greatest we have:

$\text{Number 2} \\ \\ \text{Number 1} \\ \\ \text{Number 3} \\ \\ \text{Number 2}$

Put another way:

$\sqrt{63} \\ \\ \sqrt{79} \\ \\ \sqrt{143} \\ \\ 4\pi$

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2 years ago

the volume of a cylinder is given by the formula v=3.14r^2h, where r is the radius of the cylinder and h is the height. suppose

photoshop1234 [79]

we know that

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$V=3.14 r^{2} h$

where

r is the radius of the cylinder

h is the height of the cylinder

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Substitute the values in the formula above

$V=3.14*(x+8)^{2}*(2x+3)$

$V=3.14*(x^{2}+16x+64)*(2x+3) \\ V=3.14 *(2x^{3} +3x^{2} +32x^{2} +48x+128x+192)\\ V=3.14*(2x^{3} +35x^{2} +176x+192)$

therefore

<u>the answer is</u>

The volume of the can is equal to

$V=3.14 *(2x^{3} +35x^{2} +176x+192)\ units ^{3}$

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