The exponential function models the value v of the car after t years is V = 27000 * (0.93)^t
<h3>How to determine the exponential model?</h3>
The given parameters are:
Initial value, a = $27,000
Depreciation rate, r = 7%
The value of the car is then calculated as:
V = a * (1 -r)^t
Substitute known values
V = 27000 * (1 - 7%)^t
Evaluate the difference
V = 27000 * (0.93)^t
Hence, the exponential function models the value v of the car after t years is V = 27000 * (0.93)^t
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To find W⊥, you can use the Gram-Schmidt process using the usual inner-product and the given 5 independent set of vectors.
<span>Define projection of v on u as </span>
<span>p(u,v)=u*(u.v)/(u.u) </span>
<span>we need to proceed and determine u1...u5 as: </span>
<span>u1=w1 </span>
<span>u2=w2-p(u1,w2) </span>
<span>u3=w3-p(u1,w3)-p(u2,w3) </span>
<span>u4=w4-p(u1,w4)-p(u2,w4)-p(u3,w4) </span>
<span>u5=w5-p(u4,w5)-p(u2,w5)-p(u3,w5)-p(u4,w5) </span>
<span>so that u1...u5 will be the new basis of an orthogonal set of inner space. </span>
<span>However, the given set of vectors is not independent, since </span>
<span>w1+w2=w3, </span>
<span>therefore an orthogonal basis cannot be found. </span>
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