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Crazy boy [7]
3 years ago
6

What is the slope of a line that is perpendicular to the line whose equation is 8y−5x=11?

Mathematics
2 answers:
garik1379 [7]3 years ago
8 0

Answer:

The slope of the perpendicular line will be -8/5, or -1.6

Step-by-step explanation:

First we need to rearrange the equation to show the slope, putting in the format y = sx + c:

8y - 5x = 11\\8y =  5x + 11\\y = \frac{5}{8}x + \frac{11}{8}

So the given line has a slope of 5/8.

A line perpendicular to that will have a negative reciprocal of that slope, so it's slope will be -8/5.

ElenaW [278]3 years ago
4 0

9514 1404 393

Answer:

  -8/5

Step-by-step explanation:

When you solve for y, the slope of the line is the x-coefficient. For the given line, that is ...

  8y = 5x +11 . . . . . add 5x

  y = 5/8x +11/8 . . . . divide by 8

The given line has a slope of 5/8. The perpendicular line will have a slope that is the opposite of the reciprocal of this:

  -1/(5/8) = -8/5 . . . . slope of perpendicular line

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Irina-Kira [14]

Answer:

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Step-by-step explanation:

28/21 is the equivalent to 4/3.

We know this is the fraction we are looking for because 28 + 21 = 49

Hope that helps!

4 0
2 years ago
Help please ASAP thank you!! your awesome if you help
12345 [234]

Answer:

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Step-by-step explanation:

The diagonal would be 14√2.

The formula for area using the diagonal is 1/2d².

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For perimeter, s²+s²=392

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s=√196

s=14

14x4=56

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3 years ago
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kondor19780726 [428]
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