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Lyrx [107]
3 years ago
8

On a coordinate plane, a piecewise function has two lines. The first line has an open circle at (negative 1, 3) and continues ho

rizontally along y = 3 with an arrow instead of an endpoint. The second line has a closed circle at (negative 1, negative 2) and goes down toward (5, negative 5), with an arrow instead of an endpoint.
A linear piecewise function is represented by the graph.

Use the graph to evaluate the function.

When x = –5, y =
.

When x = –1, y =
.

When x = 3, y =
.
Mathematics
2 answers:
kaheart [24]3 years ago
5 0

Answer:

when x=-5, y= 3

when x= -1, y= -2

when x=3, y= -4

Step-by-step explanation:

thats right on edge

Serggg [28]3 years ago
3 0

Answer:

when x=-5, y= 3

when x= -1, y= -2

when x=3, y= -4

Step-by-step explanation:

right on edge

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Find the point P along the directed line segment from point A(–13, 6) to point B(2, 20) that divides the segment in the ratio 2
VARVARA [1.3K]

Answer:

(-4, 14.4)

Step-by-step explanation:

The midpoint formula is expressed as;

M(X, Y) = {(ax1+bx2/a+b), ay1+by2/a+b}

Get X;

X = ax1+bx2/a+b

X = -13(2)+ 2(3)/2+3

X = -26+6/5

X = -20/5

X = -4

Get Y:

Y =ay1+by2/a+b

Y = 2(6)+3(20)/2+3

Y = 12+60/5

Y = 72/5

Y = 14.4

Hence the coordinate of point P dividing A and B in the ratio 2 to 3 is

(-4, 14.4)

5 0
3 years ago
Help ASAP.
denpristay [2]

1.\\A(n)=-2\cdot5^{n-1}\\\\\text{Find the first, fourth, and eighth terms}\\\text{It means}\ A(1),\ A(4)\ \text{and}\ A(8).\\\\\text{Substitute}\ n=1,\ n=4\ \text{and}\ n=8\ \text{in}\ A(n):\\\\A(1)=-2\cdot5^{1-1}=-2\cdot5^0=-2\cdot1=-2\\\\A(4)=-2\cdot5^{4-1}=-2\cdot5^3=-2\cdot125=-250\\\\A(8)=-2\cdot5^{8-1}=-2\cdot5^7=-2\cdot78,125=-156,250\\\\\boxed{Answer:\ a)\ -2,\ -250,\ -156,250}.


2.\\a_1=-6,\ r=2\\\\\text{The formula of a n-th term of geometric sequence}\\\\a_n=a_1r^{n-1}\\\\\text{Substitute:}\\\\a_n=-6\cdot2^{n-1}=-6\cdot2^n\cdot2^{-1}=-6\cdot2^n\cdot\dfrac{1}{2}=-3\cdot2^n\\\\\boxed{Answer:\ A(n)=a_n=-3\cdot2^n}

4 0
3 years ago
A plane flying with a constant speed of 14 km/min passes over a ground radar station at an altitude of 4 km and climbs at an ang
olchik [2.2K]

Answer:

the rate from the plane to the radar station increasing 3 minutes later is 19.81 km/min

Step-by-step explanation:

A plane flying with a constant speed of 14 km/min passes over a ground radar station at an altitude of 4 km and climbs at an angle of 45 degrees. At what rate is the distance from the plane to the radar station increasing 3 minutes later?

speed (Δs₁)= change in distance(Δd₁) /(Δt₁)change in time

mathematically,

\frac{Δd₁}{Δt₁} = Δs₁

= 14 km/min = \frac{Δd}{Δt}

and will are to find the speed after passes the radar

=Δs₂  km/min = \frac{Δd₂}{Δt₂}

to find d₁ and d₂ with respect to angle 45 degree at 4km

sin 45 = opp/hyp = 4/d₁

d₁ = 4/sin45 = 5.66km

tan 45 == opp/adj = 4/d₂

d₂ =4/tan45 =  4km

for three minute increment,

=3 x d₁ x Δs₁ = 3 x d₂ Δs₂

= 3x5.66x14 = 3x 4 xΔs₂

= 237.72 = 12Δs₂

=Δs₂ = 19.81km/min

7 0
3 years ago
I need help with this math, it is hard and I’m not good at it. I don’t understand this math so plz help me.
klasskru [66]
142 hope I’m right this time
6 0
3 years ago
Read 2 more answers
Select the correct answer. The volume of one of the Great Lakes is 3. 5 × 103 cubic kilometers. If there are 6. 3 × 107 fish in
valentinak56 [21]

The average number of fish per cubic kilometer is 1. 8 \times 10^4.

The correct option is B.

Given

The volume of one of the Great Lakes is 3.5 × 103 cubic kilometers.

The number of fish in the lake = 6. 3 × 107.

<h3>What is the average value?</h3>

The average is the middle value of the given data set and is calculated by adding up all the numbers and dividing the result by the total quantity of figures added.

The average number of fish per cubic kilometer is given by;

\rm \text{The average number of fish per cubic kilometer}= \dfrac{Number \ of \ fish \ in \ lake}{Total \ volume \ of \ lake}

Substitute all the values in the formula;

\rm \text{The average number of fish per cubic kilometer}= \dfrac{Number \ of \ fish \ in \ lake}{Total \ volume \ of \ lake}\\\\ \text{The average number of fish per cubic kilometer}= \dfrac{6.3\times 10^7}{3.5\times 10^3}\\ \text{The average number of fish per cubic kilometer}= 1.8 \times 10^4

Hence, the average number of fish per cubic kilometer is 1. 8 \times 10^4.

To know more about the Average rate click the link given below.

brainly.com/question/12395856

5 0
3 years ago
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