(x^2-2)^2-10(x^2-2)+21=0 find one value of x that is a solution to the equation
1 answer:
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Part A:
Let the width of the rectangle be = x inches
As given, the length of a rectangle is 3 more inches than the width so let the length of the rectangle be = x+3 inches
Perimeter is given as = 54 inches
Perimeter =
Equation becomes:
=54
Part B:
Solving the equation we get
Hence, the width of the rectangle is 12 inches
Length = x+3 = 12+3 = 15 inches
Hence, length of the rectangle is 15 inches.