Question

WILL MARK BRAINLIEST IF CORRECT PLEASE HELP

Answer 1

Answer:

$\frac{4\sqrt{7}}{7} \text{ and } \frac{3\sqrt{7}}{7}$

Step-by-step explanation:

if $\sec x = \frac{4}{3}$, then that means that it is the angle of a right triangle with the hypotenuse equal to 4 and one of the legs (specifically the adjacent leg) equal to 3, since sec(x) is defined as hypotenuse over the adjacent side.

The other leg (specifically the opposite one) will be equal to $\sqrt{16-9} = \sqrt{7}$ by the pythagorean theorem, so csc(x) = hypotenuse over opposite side = $\frac{4}{\sqrt{7}}=\frac{4\sqrt{7}}{7}$.

cot(x) is defined as adjacent over opposite, which is equal to $\frac{3}{\sqrt{7}}=\frac{3\sqrt{7}}{7}$

That means that the first option, the leftmost one, is correct.