<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B20%7D%20" id="TexFormula1" title=" \sqrt{20} " alt=" \sqrt{20} " align="absmiddle

3 years ago

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1 answer:

7 0

$4.472135955$

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marysya [2.9K]

This is a pretty complex problem

6 0

3 years ago

Alex777 [14]

0.53(3) + 5 = <span>6.59
</span><span>6.59 is the answer.
</span>

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2 years ago

Yuri [45]

8.25

Hope I helped! ( Smiles )

4 0

3 years ago

swat32

Answer:

Test statistic, $t_{s} = -0.603$ (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

$\bar{d} = \frac{\sum x-y}{n}$

$\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625$

Standard deviation: $SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1} }$

$\sum d^{2} = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2} = 63$

$SD = \sqrt{\frac{63 - 8 * (-0.625)^2}{8-1} }$

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

$t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n} } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8} }$

$t_{s} = -0.6033$

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3 years ago

Korvikt [17]

T(x)= 14x + 70(930-x)

4 0

3 years ago