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Eduardwww [97]
2 years ago
5

Find the value of a and b of a+root5 is (root5+root3)(root5-root3)​

Mathematics
1 answer:
Aleksandr-060686 [28]2 years ago
3 0

Given:

Consider the value of a+b\sqrt{5} is (\sqrt{5}+\sqrt{3})(\sqrt{5}-\sqrt{3}).

To find:

The values of a and b.

Solution:

According to the given information,

a+b\sqrt{5}=(\sqrt{5}+\sqrt{3})(\sqrt{5}-\sqrt{3})

a+b\sqrt{5}=(\sqrt{5})^2-(\sqrt{3})^2            [\because a^2-b^2=(a-b)(a+b)]

a+b\sqrt{5}=5-3

a+b\sqrt{5}=2

It can be written as

a+b\sqrt{5}=2+0\sqrt{5}

On comparing both sides, we get

a=2,b=0

Therefore, the value of a is 2 and the value of b is equal to 0.

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Answer:

2y - 15

Step-by-step explanation:

well 15 LESS than TWICE a number. okay so let’s start off by making a variable for the unknown number.... y. the variable is y. so now we have to think, TWICE that number, but we don’t know the number.

Now that we have the variable and we know it has to be doubled, let’s start off making the first half... we can out that into 2y. which is 2 multiplied by the unknown number.

now that we have the first half done, we have to take the 15 less. Less can mean  or subtract in this kind of situation. but for this certain scenario, it will be subtraction. so the equation would be 2y - 15.

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3 years ago
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nignag [31]

S is 27. SRT is 63 becuase of the vertical angles theorem. All angles of a triangle add up to 180, and you already have the other two angles. So its 27

8 0
3 years ago
What is the radius of a circle with the equation x^2+y^2+6x-2y+3?
atroni [7]

Answer:

r = √13

Step-by-step explanation:

Starting with x^2+y^2+6x-2y+3, group like terms, first x terms and then y terms:  x^2 + 6x            + y^2 -2y             = 3.  Please note that there has to be an " = " sign in this equation, and that I have taken the liberty of replacing " +3" with " = 3 ."  

We need to "complete the square" of x^2 + 6x.  I'll just jump in and do it:  Take half of the coefficient of the x term and square it; add, and then subtract, this square from x^2 + 6x:     x^2 + 6x  + 3^2 - 3^2.  Then do the same for y^2 - 2y:  y^2 - 2y + 1^2 - 1^2.

Now re-write the perfect square x^2 + 6x + 9 by (x + 3)^2.  Then we have x^2 + 6x + 9 - 9; also y^2 - 1y + 1 - 1.  Making these replacements:

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Then the original equation now looks like (x + 3)^2 + (y - 1)^2 = 13, and this 13 is the square of the radius, r:  r^2 = 13, so that the radius is r = √13.


8 0
2 years ago
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If the cost of a dozen eggs rises from .99 to 1.34 what is the percent of the increase
Amiraneli [1.4K]
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increase = \frac{1.34 - .99}{.99} \times 100
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