Answer:
a) 19 students
b) the mean 3 9/19
the median 3
the mode 3
c) the range 6
Step-by-step explanation:
The data set shows that
0 points gets 1 student,
1 point gets 1 student,
2 points get 2 students,
3 points get 6 students,
4 points get 4 students,
5 points get 3 students and
6 points get 2 students.
a) There are 1+1+2+6+4+3+2=19 students.
b) The mean is

The average score is 3 9/19 points.
The median is 10th term in the data set - 3 points (means the middle score in the data set)
The mode is 3 points (means most happened score)
c) The range of the data is 6-0=6 points.
1) False
Adjacent angles must share a common side/ray.
2) B and D
Adjacent angles are those that are directly next to each other and share a common side.
3) C
Angles 1 and 2 are congruent. Angles 3 and 4 are congruent. Both of these pairs have angles that are opposite each other.
4) B
Angles 1 and 2 add up to 180. Angles 3 and 4 add up to 180. Both of these pairs of angles are supplementary.
5) A
These angles are directly next to each other and share a common side.
Hope this helps!! :)
Answer:
B. 2⁵ + 7²
Step-by-step explanation:
2 to the fifth power is: 2⁵
7 squared (7 to the second power) is: 7²
Total 175 students.
102 students go to movies at least twice a week and 73 students either go 1 times or not going to the movies.
So
Students go 0-1 times per week = 73/175 = 0.4172 = 41.71%
Answer: last option
41.71%
The question given is incomplete, I googled and got the complete question as below:
You are a waterman daily plying the waters of Chesapeake Bay for blue crabs (Callinectes sapidus), the best-tasting crustacean in the world. Crab populations and commercial catch rates are highly variable, but the fishery is under constant pressure from over-fishing, habitat destruction, and pollution. These days, you tend to pull crab pots containing an average of 2.4 crabs per pot. Given that you are economically challenged as most commercial fishermen are, and have an expensive boat to pay off, you’re always interested in projecting your income for the day. At the end of one day, you calculate that you’ll need 7 legal-sized crabs in your last pot in order to break even for the day. Use these data to address the following questions. Show your work.
a. What is the probability that your last pot will have the necessary 7 crabs?
b. What is the probability that your last pot will be empty?
Answer:
a. Probability = 0.0083
b. Probability = 0.0907
Step-by-step explanation:
This is Poisson distribution with parameter λ=2.4
a)
The probability that your last pot will have the necessary 7 crabs is calculated below:
P(X=7)= {e-2.4*2.47/7!} = 0.0083
b)
The probability that your last pot will be empty is calculated as:
P(X=0)= {e-2.4*2.40/0!} = 0.0907