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Nuetrik [128]
3 years ago
6

DeanR where.are youuu i need ur helppppppp

Mathematics
2 answers:
Tatiana [17]3 years ago
8 0

Do the formula length times width times height.

Then, round like you normally would!

And for the second one, just multiply 2.5 x 6!

uranmaximum [27]3 years ago
7 0

Wow a shoutout!


The greatest common factor of two numbers is what it sounds like, the biggest number that divides both, i.e. the biggest number who has multiples that are the original numbers.  


The way we do it is we factor each number and then we just pick out all the common prime factors and multiply them together.  Here 56=2×2×2×7 and  92=2×2×23 so there are two factors of 2 in common, so a GCF of 2×2=4.  In symbols:


GCF(56,92)=GCF(2^3(7), 2^2(23)) = 2^2 = 4



22.9 × 7.5 × 4.6 = 790.05


Rounded, 790 cubic meters


5 × 2 × 4 × (2 1/2)^3 = 5 × 2 × 4 × (5/2)^3 = 5^4 = 625 cubic inches


12 meters / (3 meters / hour) = 4 hours


180 \textrm{ packages} \times \dfrac{48 \textrm{ dollars}}{2 \textrm{cases}} \times \dfrac{ 1 \textrm{ case}}{12 \textrm{ packages}} = 360 \textrm{ dollars}}




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\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}

Step by step explanation:

\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies  1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\

\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}

\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}

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