Answer:
2/5, 3/7, 1/2, 5/8, 5/6
Step-by-step explanation:
change the fractions into decimals and place them in order from least to greatest, then revert back to it's original form which would be a fraction.
<h3>
Answer: -2</h3>
===============================================
Explanation:
We use the remainder theorem. This is the idea where if we divide P(x) over (x-k), then the remainder is P(k).
Comparing x+1 to x-k shows that k = -1
It might help to rewrite x+1 as x-(-1) to get it into the form x-k better.
Plug this k value into the function
f(x) = 2x^6 + 3x^5 - 1
f(-1) = 2(-1)^2 + 3(-1)^5 - 1
f(-1) = 2(1) + 3(-1) - 1
f(-1) = 2 - 3 - 1
f(-1) = -1 - 1
f(-1) =-2
The remainder is -2
We can confirm this through synthetic division or polynomial long division.
Start from inside to the out side of the function;
h(5)=10/5=2
g(h)=g(2)=3*2=6
now, get the f inverse of x;
f(x)=y=x+6
x=y-6
replace x with y and y with x
y=x-6
so f^-1= x-6
so f^-1(g)=f^-1(6)=6-6=0
I am not sure only of the last value, but pretty sure of the rest.
are you ok
and yes
waffles are way hotter than pancakes sorry i dont make the rules here
Answer: Option C. Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)
Solution:
Conditional relative frequency single employees in grade 2:
[(Single employees in job grade 2)/(Total employees in job grade 2)]*100%=
(222/4,239)*100%=0.052370842*100%=5.2370842% approximately 5.2%
Conditional relative frequency married employees in grade 2:
[(Married employees in job grade 2)/(Total employees in job grade 2)]*100%=
(3,927/4,239)*100%=0.926397735*100%=92.6397735% approximately 92.6%
92.6%>5.2%:
Married and grade 2 (92.6%) is higher than Single and grade 2 (5.2%)
