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alexdok [17]
3 years ago
8

Which values are solutions to the inequality below? √x ≤ 5

Mathematics
1 answer:
Romashka [77]3 years ago
5 0
\sqrt{x}  \leq 5

Find the real  region  for \sqrt{x}

\sqrt{x} is real for x \geq 0

= x  \geq 0

\sqrt{x}  \leq 5

Square both sides:

( \sqrt{x} )^2  \leq 5^2

5^2 = 5*5 =25

Refine:

x  \leq 25

Answer D

hope this helps!


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If you have 2x - 4 list three input and their output values.
poizon [28]

With 2x-4 given to you, you can substitute x (input) and solve with that input to get y (output).

Ex. 2(0)-4=-4, (0, -4)

     2(1)-4=-2, (1, -2)

     2(2)-4=0, (2, 0)

4 0
3 years ago
I'm so stuck how do you do this??
Len [333]
10 1/3= 31/3
12=36/3
31/3 × 36/3=124

I hope this helped!!!:)
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4 years ago
Read 2 more answers
Help with this question, please!
uranmaximum [27]

Answer:

52 ft

Step-by-step explanation:

For each chord, the product of segment lengths is a constant. We can find that constant as the product of the segment lengths of the bisected chord:

(24 ft)·(24 ft) = 576 ft^2

Then the missing segment length (DX) of the diameter chord is ...

DX·(36 ft) = 576 ft^2

DX = (576 ft^2)/(36 ft) = 16 ft

So, the total length of the diameter chord is ...

DX +XL = 16 ft + 36 ft

DL = 52 ft

_____

We know DL is a diameter because the perpendicular bisector of any chord intersects the center of the circle.

5 0
3 years ago
A student measured the lead content of a paint sample 4 times. The standard deviation of the measurements was found to be 0.76%
Lady_Fox [76]

Answer:

CI =0.894%

Step-by-step explanation:

From the question we are told that:

Sample size n=4

Standard deviation \sigma=0.76\% of \=x

Confidence level \mu =90\%=0.90

Degree of Freedom Df=n-1=3

Therefore

Test T from table is given

 t=2.353

Generally the equation for Confidence interval CI is mathematically given by

 CI =t*\frac{\sigma}{\sqrt{n}}

 CI =2.353*\frac{0.76}{\sqrt{4}}

 CI =0.894%

6 0
3 years ago
Please answer!!
HACTEHA [7]

Answer:

See below

Step-by-step explanation:

f(x)=3x^2+6x-24\\\\f(x)=3(x^2+2x-8)\\\\f(x)+3(9)=3(x^2+2x-8+9)\\\\f(x)+27=3(x^2+2x+1)\\\\f(x)=3(x+1)^2-27

Here, we can see that the vertex of the parabola is (-1,-27) when we compare to the equation y=(x-h)^2+k with vertex (h,k).

A second point you could plot is the y-intercept, when x=0:

f(0)=3(0+1)^2-27\\\\f(0)=3-27\\\\f(0)=-24

So, your y-intercept is (0,-24).

8 0
2 years ago
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