3 years ago

Which values are solutions to the inequality below? √x ≤ 5

1 answer:

5 0

$\sqrt{x} \leq 5$

Find the real region for $\sqrt{x}$

$\sqrt{x}$ is real for $x \geq 0$

$= x \geq 0$

$\sqrt{x} \leq 5$

Square both sides:

$( \sqrt{x} )^2 \leq 5^2$

$5^2 = 5*5 =25$

Refine:

$x \leq 25$

Answer D

hope this helps!

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