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alexdok [17]
3 years ago
8

Which values are solutions to the inequality below? √x ≤ 5

Mathematics
1 answer:
Romashka [77]3 years ago
5 0
\sqrt{x}  \leq 5

Find the real  region  for \sqrt{x}

\sqrt{x} is real for x \geq 0

= x  \geq 0

\sqrt{x}  \leq 5

Square both sides:

( \sqrt{x} )^2  \leq 5^2

5^2 = 5*5 =25

Refine:

x  \leq 25

Answer D

hope this helps!


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