Answer:
D)
Step-by-step explanation:
ASSUMING NORMAL DISTRIBUTION, LESS THAN 10% AT LOWER END
OF 15.34 MEANS [DENOTING MEAN BY M AND Standard Deviation. BY S]
M±AS=20%....................M-AS=15.34
FOR 20% LEVEL .......A=1.281........FROM TABLES
M-1.281×S=15.34............................1
SIMILARLY
M±BS=40%...................M+BS=16.31
FOR 40% LEVEL .............B=0.841...................FROM TABLES
M+0.841×S=16.31.............................2
EQN.2 - EQN.1
2.122×S=0.97
S=0.457=0.46
M=15.926= 15.93
HENCE, D IS THE ANSWER
that is D. μ = 15.93, σ =.46
Answer:
$48.60
Step-by-step explanation:
4 7/5 is a funny way to express a fraction... but anway..... if this is correct, then the answer is as follows:
5/6 kg ------> cost $7.50
1 kg ----> costs $7.50 ÷ 5/6 kg = $9
4 7/5 kg ------> costs $9 x (4 7/5) = $9 x (27/5) = $48.60
Answer:
13.989 rounded to nearest tenth is 14.0.
Step-by-step explanation:
Answer: A (I think)
Step-by-step explanation: it would be left of 9 since it’s 8.77496438739
81 square rooted is 9 so 77 square rooted is less than 81 square rooted
And a number line counts up the more you go right.
Answer:
1,805 kg.
Step-by-step explanation:
We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.
First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.
Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.
Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.
