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amm1812
3 years ago
6

Need help with this question! Will attach pic! A satellite is to be put into an elliptical orbit around a moon as shown below.Th

e moon is a sphere with radius of 1000 km. Determine an equation for the ellipse if the distance of the satellite from the surface of the moon varies from 953 km to 466 km
Mathematics
1 answer:
Darina [25.2K]3 years ago
4 0
An equation for the ellipse ( standard form ):
x²/a²  +  y²/b² = 1
Here is:  a - semi-major axis and b - semi-minor axis.
Radius of the moon is 1,000 km and the distance from the surface of the moon to the satellite varies from 953 km to 466 km.
a = 1,000 + 953 = 1,953 km
b = 1,000 + 466 = 1,466 km
Answer:
The equation is  x² / 1,953²  + y² / 1,466² = 1
or: x²/3,814,209  +   y²/2,149,156  = 1
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4 years ago
I really need help with this, my teacher doesn't really teach and I'm stumped again.​
yarga [219]

Answer:

JMK = 54

JKH = 126

HLK = 90

HJL = 27

LHK = 63

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Step-by-step explanation:

Just use 180 for total angles in each triangle. Vertical angles mean the opposite to 126 is 126 and the other two that make up the inner vertices are (360- 126*2)/2 = 54

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5 0
3 years ago
There are seven cats in my neighborhood, with an average of $41$ whiskers each. If one of the cats has $17$ whiskers, how many w
harkovskaia [24]

Answer:

Each of the other cats have 45 whiskers on average.

Step-by-step explanation:

Let x represent the average number of whisker of each cat.

We have been given that there are 7 cats in my neighborhood, with an average of 41 whiskers each.

The total number of whiskers of six cats would be 6x.

Since one of the cats has 17 whiskers, so the total number of whiskers of 7 cats would be 6x+17

We will use average formula to solve our given problem.

\text{Average}=\frac{\text{Sum of data points}}{\text{Number of data points}}

Upon substituting our given values, we will get:

41=\frac{6x+17}{7}

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41*7=\frac{6x+17}{7}*7

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Switch sides:

6x=270

\frac{6x}{6}=\frac{270}{6}

x=45

Therefore, the each of the other cats have 45 whiskers on average.

8 0
3 years ago
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