Triangle A
hypotenuse: 3y + x
leg: y - x
Triangle B
hypotenuse: y + 5
leg: x + 5
Congruency => 3y + x = y + 5 and y - x = x + 5
Solve the system
3y + x = y + 5 -> 2y + x = 5
y - x = x + 5 -> y - 2x = 5
2y + x = 5
-2y + 4x = -10
5x = -5
x = -1
y = (5 -(-1)) / 2 = 6/2 = 3
Verify:
hypotenuses
3y + x = 9 - 1 = 8
y + 5 = 3 + 5 = 8
Legs:
y - x = 3 -(-1) = 3 + 1 = 4
x + 5 = -1 + 5 = 4.
Then both hypotenuses and both legs are congruent.
Answer: x = -1 and y = 3
3x - 2y - 1 = 0
y = 5x + 4
3x - 2(5x + 4) - 1 = 0
3x - 10x - 8 - 1 = 0
-7x - 9 = 0
-7x = 9
x = -9/7
y = 5x + 4
y = 5(-9/7) + 4
y = -45/7 + 4
y = -45/7 + 28/7
y = - 17/7
solution is (-9/7, -17/7)
Answer:
(5x-4y)=19
5×19-4×19
95-76
19
Step-by-step explanation:
x+2y=8
x=8-2
x=6
Answer:
[2] x = -5y - 4
// Plug this in for variable x in equation [1]
[1] 2•(-5y-4) - 5y = 22
[1] - 15y = 30
// Solve equation [1] for the variable y
[1] 15y = - 30
[1] y = - 2
// By now we know this much :
x = -5y-4
y = -2
// Use the y value to solve for x
x = -5(-2)-4 = 6
Solution :
{x,y} = {6,-2}
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Terms and Topics
Linear Equations with Two Unknowns
Solving Linear Equations by Substitution
Related Links
Algebra - Linear Systems with Two Variables
Step-by-step explanation:
Answer:
I believe that there is 3087 multiples of 5
Step-by-step explanation:
