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3 years ago

The sum of two numbers is 18 their difference is 4

Mathematics

1 answer:

lianna [129]3 years ago

5 0

Answer:

7 and 11

Step-by-step explanation:

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Bridgette wants to be a princess for Halloween. When she gets to the costume store, she realizes there are many options. There a

gulaghasi [49]

Answer:

120

Step-by-step explanation:

an easy way of looking at it is

5x8x3

4 0

3 years ago

3-4/5X-2/3–3/15+3/5divided by -3/2

deff fn [24]

Answer:

-2(6x-13)/15

Step-by-step explanation:

This is done by simplifying the expression as well as combining like terms

4 0

3 years ago

-6 - 3(2x + 4) = 18what’s the answer

Brrunno [24]

Answer:

$x=-6$

Step-by-step explanation:

$-6-3\left(2x+4\right)=18$

Add 6 to both sides:

$-6-3\left(2x+4\right)+6=18+6$

$-3\left(2x+4\right)=24$

Divide both sides by -3:

$\frac{-3\left(2x+4\right)}{-3}=\frac{24}{-3}$

$2x+4=-8$

Subtract 4 from both sides:

$2x+4-4=-8-4$

$2x=-12$

Divide both sides by 2:

$\frac{2x}{2}=\frac{-12}{2}$

$x=-6$

7 0

3 years ago

Please help !! Will mark brainliest answer

Norma-Jean [14]

Answer:

x = 12

Step-by-step explanation:

18:24 (comparing the same sides for the similar shapes; 18 and 24) when simplified down is equal to 3:4.

Using this 3:4 scale factor we can find the missing side x.

Solving for x :

$\frac{3}{4}$ × 16 = 12

x = 12

OR: Set up a proportion:

$\frac{24}{16}$ × $\frac{18}{x}$

cross-multiply

16 × 18 = 288

24 × x = 24x

288 = 24x

x = 12

3 0

3 years ago

Find the two intersection points

bogdanovich [222]

Answer:

Our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

Step-by-step explanation:

We want to find where the two graphs given by the equations:

$\displaystyle (x+1)^2+(y+2)^2 = 16\text{ and } 3x+4y=1$

Intersect.

When they intersect, their x- and y-values are equivalent. So, we can solve one equation for y and substitute it into the other and solve for x.

Since the linear equation is easier to solve, solve it for y:

$\displaystyle y = -\frac{3}{4} x + \frac{1}{4}$

Substitute this into the first equation:

$\displaystyle (x+1)^2 + \left(\left(-\frac{3}{4}x + \frac{1}{4}\right) +2\right)^2 = 16$

Simplify:

$\displaystyle (x+1)^2 + \left(-\frac{3}{4} x + \frac{9}{4}\right)^2 = 16$

Square. We can use the perfect square trinomial pattern:

$\displaystyle \underbrace{(x^2 + 2x+1)}_{(a+b)^2=a^2+2ab+b^2} + \underbrace{\left(\frac{9}{16}x^2-\frac{27}{8}x+\frac{81}{16}\right)}_{(a+b)^2=a^2+2ab+b^2} = 16$

Multiply both sides by 16:

$(16x^2+32x+16)+(9x^2-54x+81) = 256$

Combine like terms:

$25x^2+-22x+97=256$

Isolate the equation:

$\displaystyle 25x^2 - 22x -159=0$

We can use the quadratic formula:

$\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In this case, a = 25, b = -22, and c = -159. Substitute:

$\displaystyle x = \frac{-(-22)\pm\sqrt{(-22)^2-4(25)(-159)}}{2(25)}$

Evaluate:

$\displaystyle \begin{aligned} x &= \frac{22\pm\sqrt{16384}}{50} \\ \\ &= \frac{22\pm 128}{50}\\ \\ &=\frac{11\pm 64}{25}\end{aligned}$

Hence, our two solutions are:

$\displaystyle x_1 = \frac{11+64}{25} = 3\text{ and } x_2 = \frac{11-64}{25} =-\frac{53}{25}$

We have our two x-coordinates.

To find the y-coordinates, we can simply substitute it into the linear equation and evaluate. Thus:

$\displaystyle y_1 = -\frac{3}{4}(3)+\frac{1}{4} = -2$

And:

$\displaystyle y _2 = -\frac{3}{4}\left(-\frac{53}{25}\right) +\frac{1}{4} = \frac{46}{25}$

Thus, our two intersection points are:

$\displaystyle (3, -2) \text{ and } \left(-\frac{53}{25}, \frac{46}{25}\right)$

6 0

3 years ago