Given :
Electronic configuration of an electron :
.
To Find :
The element having such an electronic configuration .
Solution :
We know , the sum of all the power of s and p in all the orbit gives total number of atoms in elements .
So , atomic number is :
Since , the atomic number is 18 .
Therefore , the element is Argon .
Hence , this is the required solution .
Answer:
Substitute the known values into the formula: 140 = 7(w)(5).
Solve for the unknown: w = 4 m.
Check:
140 = 7(w)(5) => w = 140/(5 x 7) = 140/35 = 4. => Correct.
Substitute the known values into the formula:
7 = 140(w)(5).
Solve for the unknown: w = 7 m.
Check:
7 = 140(w)(5) => w = 7/(140 x 5) = 7/700 = 1/100. => Incorrect.
Substitute the known values into the formula:
5 = 7(w)(140).
Solve for the unknown: w = 2 m.
Check: 5 = 7(w)(140) => w = 5/(7 x 140) = 5/840 = 1/168. => Incorrect.
Hope this helps!
:)
I hope this helps you
0,2x+0,2+0,5x= -0,3x+1,2
0,7x+0,3x=1,2-0,2
x=1
X\6=12\9
multiply both sides by 6
x=12\9 x 6
x=8
Multiply the first equation by 4 (so that both equations will have 8x terms) and then subtract:
8x-20y = -24
8x +3y = 68
------------
0 -23y = -92
Now divide both sides by -23:
y = 4
Find x by plugging y=4 into either equation:
8x +3(4) = 68
8x = 68 - 12
8x = 56
x = 7
So the answer is ordered pair is (7,4)
