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4vir4ik [10]
4 years ago
7

Can someone help me with this problem [-64x(-5)-2x(3)]

Mathematics
2 answers:
galina1969 [7]4 years ago
5 0
The answer is 314
(^o^)
Leni [432]4 years ago
3 0
314 is the answer. I hope I helped.
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A field is 140 yards long and 90 yards wide. find its area in square feet
Debora [2.8K]

Convert the yards to feet.

1 yard = 3 feet.

140 yards x 3 feet per yard = 420 feet.

90 yards x 3 feet per yard = 270 feet.


Area = 420 x 270 = 113,400 square feet.

3 0
4 years ago
Find the next number in the number sequence 3, 6, 10, 15.
natulia [17]

Answer:

21

Step-by-step explanation:

3 + 3 = 6

6 + 4 = 10

10 + 5 = 15

so...

15 + 6 = 21

6 0
4 years ago
Read 2 more answers
Integrate dx/3sinx+4cosx
german

\displaystyle\int\frac{\mathrm dx}{3\sin x+4\cos x}

A standard approach would be the tangent half-angle substitution:

t=\tan\dfrac x2\implies\mathrm dt=\dfrac12\sec^2\dfrac x2\,\mathrm dx

Then

\sin x=2\sin\dfrac x2\cos\dfrac x2\implies\sin x=\dfrac{2t}{1+t^2}

\cos x=\cos^2\dfrac x2-\sin^2\dfrac x2\implies\cos x=\dfrac{1-t^2}{1+t^2}

from which we get

\mathrm dx=\dfrac2{1+t^2}\,\mathrm dt

So the integral becomes

\displaystyle\int\frac{\frac2{1+t^2}}{\frac{6t}{1+t^2}+\frac{4(1-t^2)}{1+t^2}}\,\mathrm dt=\int\frac{\mathrm dt}{3t+2(1-t^2)}=-\int\frac{\mathrm dt}{2t^2-3t-2}

Rewrite the denominator as

2t^2-3t-2=(2t+1)(t-2)

and expand the integrand into its partial fractions:

\dfrac1{2t^2-3t-2}=\dfrac15\left(\dfrac1{t-2}-\dfrac2{2t+1}\right)

We have

\displaystyle-\frac15\int\frac1{t-2}-\frac2{2t+1}\,\mathrm dt=-\frac15(\ln|t-2|-\ln|2t+1|)+C

=\dfrac15\ln\left|\dfrac{2t+1}{t-2}\right|+C

=\dfrac15\ln\left|\dfrac{2\tan\frac x2+1}{\tan\frac x2-2}\right|+C

6 0
3 years ago
Answer pleaseeeee<br> Find the value of x in the triangle shown below.
Maurinko [17]

well, keeping in mind that twin sides stemming from the same "vertex" make twin angles at the "base", Check the picture below.

7 0
1 year ago
Any answers? My last question. ;-;
faltersainse [42]
? 42
sorry if i’m wrong
7 0
3 years ago
Read 2 more answers
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