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4vir4ik [10]
3 years ago
7

Can someone help me with this problem [-64x(-5)-2x(3)]

Mathematics
2 answers:
galina1969 [7]3 years ago
5 0
The answer is 314
(^o^)
Leni [432]3 years ago
3 0
314 is the answer. I hope I helped.
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If JK LM , which statement is true ?
Alika [10]
The answer to this question would be: B. JK and LM meet at a right angle.

The reversed T symbol in this question means "perpendicular". That means the JK and LM line have 90-degree angle difference. A straight angle is 180 degree and right angle mean 90 degrees.
A perpendicular line should be in the same plane and intersect each other.
7 0
3 years ago
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Jill needs $40 to buy a toy she really wants. She has $15 atreadyHer birthday is coming up and she is hoping for at least the am
OleMash [197]

Answer:

40-15=35

Step-by-step explanation:

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7 0
3 years ago
Nswer two questions about Systems A AA and B BB: System A AA start text, end text System B BB { − 3 x + 12 y = 15 7 x − 10 y = −
rjkz [21]

Answer:

(Choice C) C Replace one equation with a multiple of itself

Step-by-step explanation:

Since system A has the equations

-3x + 12y = 15 and 7x - 10y = -2 and,

system B has the equations

-x + 4y = 5 and 7x - 10 y = -2.

To get system B from system A, we notice that equation -x + 4y = 5 is a multiple of -3x + 12y = 15 ⇒ 3(-x + 4y = 5) = (-3x + 12y = 15).

So, (-x + 4y = 5) = (1/3) × (-3x + 12y = 15)

So, we replace the first equation in system B by 1/3 the first equation in system A to obtain the first equation in system B.

So, choice C is the answer.

We replace one equation with a multiple of itself.

7 0
3 years ago
What is the simplified form of −x2 (2x3 + 5x2 + 6x)?
allsm [11]
I Believe It’s 2x^5-5x^4-6x^3
6 0
3 years ago
Solving Rational equations. LCD method. Show work. Image attached.
Ugo [173]

Answer:

k=\frac{1}{2}

Step-by-step explanation:

The given rational equation is

\frac{5k}{k+2}+\frac{2}{k}=5

The Least Common Denominator is

k(k+2)

Multiply each term by the LCD.

k(k+2)\times \frac{5k}{k+2}+k(k+2)\times \frac{2}{k}=5k(k+2)

Simplify;

k\times \frac{5k}{1}+(k+2)\times \frac{2}{1}=5k(k+2)

\Rightarrow k(5k)+2(k+2)=5k(k+2)

Expand;

\Rightarrow 5k^2+2k+4=5k^2+10k

Group similar terms;

\Rightarrow 5k^2-5k^2+2k-10k=-4

\Rightarrow -8k=-4

Divide by -8.

k=\frac{1}{2}

5 0
3 years ago
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