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telo118 [61]
3 years ago
10

Tan?cos? Sin? What is the m

Mathematics
1 answer:
AlexFokin [52]3 years ago
8 0

Answer:

45º

Step-by-step explanation:

Since we know the relatiionship of a 45-45-90 degree triangle, we can go two ways. Either we can use this to find CA and get the tangent of (6/6) or we can go straight to it. The hypotenuse in a 45-45-90 is always 6√2 and we know it is a right triangle so we can confirm this. So, measure of angle B is 45º.

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Trapezoid ABCD is congruent to trapezoid A"B"C"D". Which sequence of transformations could have been used to transform trapezoid
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Answer:ygggydtdgdgdfddgfs

Step-by-step explanation:

8 0
2 years ago
Hurry someone please answer plsss<br> Find the midpoint of each line segment.
djverab [1.8K]

Answer:

2.5

Step-by-step explanation:

you can use pythag theorem and divide c by two:

-3^2+4^2=c^2

9+16= 25

c=5

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4 0
3 years ago
Miguel is playing a game in which a box contains four chips with numbers written on them. Two of the chips have the number 1, on
boyakko [2]

Answer:

idk what exactly this is asking buut here is my best answer

Step-by-step explanation:

1+1=2(3+5=-1)

since 6 is the possible outcoe .idk what its exacly askign so if u can help with tht that wuld be grest .

Need 1 more brainliest

 

7 0
3 years ago
Read 2 more answers
What is the volume of this box?<br> 4 in long<br> 12in high<br> 3in wide
Natali5045456 [20]

Answer:

<h2>144 in²</h2>

Step-by-step explanation:

Multiply the length, width and height to find the volume of the box

6 0
2 years ago
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Annie’s change purse contained 5 quarters 8 dimes and 8 nickels if Annie chose 2 coin randomly without replacing them in her pur
Bogdan [553]
<h3>Answer:</h3>

2/15

<h3>Explanation:</h3>

There are 8C2 = 28 ways to choose 2 dimes from the 8 dimes in Annie's purse. There are 21C2 = 210 ways to choose 2 coins from the 21 coins in Annie's purse.

Of the 210 ways to choose 2 coins, 28 of the choices will result in 2 dimes being chosen. The probability of choosing 2 dimes is 28/210 = 2/15.

_____

<em>Comment on nCk</em>

The number of ways to choose k objects from n, when order does not matter, is ...

... n!/(k!(n -k)!)

For the computations above, we have ...

... 8C2 = 8·7/(2·1) = 28

... 21C2 = 21·20/(2·1) = 210

8 0
3 years ago
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