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lisabon 2012 [21]
3 years ago
14

How would u solve this??

Mathematics
1 answer:
Norma-Jean [14]3 years ago
4 0

Answer:

n=1, m=3, and p=-4

Step-by-step explanation:

Take the fourth root of both sides

so x^n*y^m*z^p=x*y^3*z^-4;

notice z has a negative exponent because it was in the denominator

therefore, n=1, m=3, and p=-4

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Answer:

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

Step-by-step explanation:

Given that;

the frequencies of there alternatives are;

Frequency A = 60

Frequency B = 12

Frequency C = 48

Total = 60 + 12 + 48 = 120

Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;

Relative Frequency A = Frequency A / total = 60 / 120 = 0.5

Relative Frequency B = Frequency B / total = 12 / 120 = 0.1

Relative Frequency C = Frequency C / total = 48 / 120 = 0.4

therefore;

CLASS     FREQUENCIES     RELATIVE FREQUENCIES

A                        60                                 0.5

B                        12                                  0.1

C                        48                                 0.4

TOTAL              120                                  1

5 0
3 years ago
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