Question

If f(y) = 8 + e-9y, find f'(y). Use exact values.

Answer 1

Answer:

$f'(y) = -9e^{-9y}$

Step-by-step explanation:

The given function is :

$f(y) = 8 + e^{-9y}$

We need to find the value of f'(y).

$f'(y)=\dfrac{d}{dy}[8+e^{-9y}]$

$=\dfrac{d}{dy}(8)+\dfrac{d}{dy}(e^{-9y})\\\\=0+e^{-9y}\dfrac{d}{dy}(-9y)\\\\=-9e^{-9y}$

So, the value of f'(y) is equal to $-9e^{-9y}$.