Factor the GCF: 9a4b3 + 24a3b2 − 15a2b.
2 answers:
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Answer:
Adults=8
Childrens=2
Seniors=2
Step-by-step explanation:
Children $4
Adults $6
Seniors $5
There are an equal number of seniors and children.
The entire group spent a total of $66.
If 11 adults attended, the total amount will be $66 and the number of senior and childrens will be the same, 0. But this is not possible because the statement says that childrens and seniors are part of the group.
If we add the charges of childrens and seniors is equal to $9.
Assuming that the group has 2 childrens and 2 seniors the add is equal to:
Now we substract the result from the total amount:
48 is multiple of 6, this means we have in the group 8 adults, 2 childrens and 2 seniors.
Using the z-distribution, it is found that the 95% confidence interval for the difference is (-1.3, -0.7).
<h3>What are the mean and the standard error for each sample?</h3>Considering the data given:
The mean is the subtraction of the means, hence:
The standard error is the square root of the sum of the variances of each sample, hence:
It is given by:
We have a 95% confidence interval, hence the critical value is of z = 1.96.
Then, the bounds of the interval are given as follows:
More can be learned about the z-distribution at brainly.com/question/25890103
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The answer is 134 ft^2
the area of the smaller rectangle:
the area of the other rectangle:
the area of the whole shape:
good luck
the area of the smaller rectangle:
the area of the other rectangle:
the area of the whole shape:
good luck