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lina2011 [118]
3 years ago
11

HELP ME PLEASEEEEEEEEE

Mathematics
1 answer:
OLga [1]3 years ago
4 0

Answer:

is it 56 units²? if not sorry

You might be interested in
The Slow Ball Challenge or The Fast Ball Challenge.
cupoosta [38]

Answer:

Fast ball challenge

Step-by-step explanation:

Given

Slow Ball Challenge

Pitches = 7

P(Hit) = 80\%

Win = \$60

Lost = \$10

Fast Ball Challenge

Pitches = 3

P(Hit) = 70\%

Win = \$60

Lost = \$10

Required

Which should he choose?

To do this, we simply calculate the expected earnings of both.

Considering the slow ball challenge

First, we calculate the binomial probability that he hits all 7 pitches

P(x) =^nC_x * p^x * (1 - p)^{n - x}

Where

n = 7 --- pitches

x = 7 --- all hits

p = 80\% = 0.80 --- probability of hit

So, we have:

P(x) =^nC_x * p^x * (1 - p)^{n - x}

P(7) =^7C_7 * 0.80^7 * (1 - 0.80)^{7 - 7}

P(7) =1 * 0.80^7 * (1 - 0.80)^0

P(7) =1 * 0.80^7 * 0.20^0

Using a calculator:

P(7) =0.2097152 --- This is the probability that he wins

i.e.

P(Win) =0.2097152

The probability that he lose is:

P(Lose) = 1 - P(Win) ---- Complement rule

P(Lose) = 1 -0.2097152

P(Lose) = 0.7902848

The expected value is then calculated as:

Expected = P(Win) * Win + P(Lose) * Lose

Expected = 0.2097152 * \$60 + 0.7902848 * \$10

Using a calculator, we have:

Expected = \$20.48576

Considering the fast ball challenge

First, we calculate the binomial probability that he hits all 3 pitches

P(x) =^nC_x * p^x * (1 - p)^{n - x}

Where

n = 3 --- pitches

x = 3 --- all hits

p = 70\% = 0.70 --- probability of hit

So, we have:

P(3) =^3C_3 * 0.70^3 * (1 - 0.70)^{3 - 3}

P(3) =1 * 0.70^3 * (1 - 0.70)^0

P(3) =1 * 0.70^3 * 0.30^0

Using a calculator:

P(3) =0.343 --- This is the probability that he wins

i.e.

P(Win) =0.343

The probability that he lose is:

P(Lose) = 1 - P(Win) ---- Complement rule

P(Lose) = 1 - 0.343

P(Lose) = 0.657

The expected value is then calculated as:

Expected = P(Win) * Win + P(Lose) * Lose

Expected = 0.343 * \$60 + 0.657 * \$10

Using a calculator, we have:

Expected = \$27.15

So, we have:

Expected = \$20.48576 -- Slow ball

Expected = \$27.15 --- Fast ball

<em>The expected earnings of the fast ball challenge is greater than that of the slow ball. Hence, he should choose the fast ball challenge.</em>

5 0
2 years ago
Pls help me and i will know if it is wrong
DENIUS [597]

9514 1404 393

Answer:

  90 miles

Step-by-step explanation:

Let d represent the distance to Grandma's house.

The speed going was ...

  speed = distance/time

  speed = d/2

The speed coming home was ...

  speed = d/2.25

The difference of these speeds is 5 miles per hour:

  d/2 -d/2.25 = 5

  2.25d -2d = 5(4.50) . . . . . multiply by 4.50

  0.25d = 22.5 . . . . . . . . . . .simplify

  d = 90 . . . . . . . . . . . . . . . . multiply by 4

Grandma's house is 90 miles away.

8 0
3 years ago
Wilma buys a new game that is priced $43.89. She gets successive discounts of 15% followed by 5% off on the game. The purchase p
jek_recluse [69]
The answer is C. 80.75%

Hope this helps!
4 0
3 years ago
Read 2 more answers
please help asap!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Phantasy [73]

Answer:

Area = 7.853981 in^2                (2.5 Pi)

Perimeter = 11.42478 in              (3.63Pi)

Step-by-step explanation:

Area

Lg semi circle area = Pi(2^2)(0.5) = 3.141593(4)0.5) = 6.283185 in^2

Sm semi circle area = Pi(1^2)(0.5) = 3.141593(2)(0.5) = 1.570796 in^2

added together = 7.853981 in^2

Perimeter

Lg semi circle perimeter = Pi(4)(0.5) + 2 = 8.283185 in

Sm semi circle perimeter = Pi(2)(0.5) = 3.141593 in

added together = 11.42478 in

5 0
3 years ago
What type of angle is shown below?<br><br> obtuse<br> acute<br> straight<br> right
sertanlavr [38]
It's an acute angle
5 0
3 years ago
Read 2 more answers
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