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3 years ago

I ONLY HAVE 5 MIN TO TURN THIS IN PLS HELP!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Alexeev081 [22]3 years ago

5 0

Answer:

4y^3 + 4x^2 -2

(work included in image)

Viktor [21]3 years ago

3 0

The answer is -2 + 4y^3 + 4x^2

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Really important, this is a quiz grade. Please provide steps. :D. Will mark Brainliest

viva [34]

Karen has $30, Rafael has $75 and Shen has $25.

Step-by-step explanation:

Given,

Total amount they have = $130

Let,

Amount of Karen = x

Amount of Rafael = y

Amount of Shen = z

According to given statement;

x+y+z=130 Eqn 1

Shen has $5 less than what Karen have.

z = x-5 Eqn 2

Rafael has 3 times what Shen has;

y = 3z Eqn 3

Putting value of z from Eqn 2 in Eqn 3

$y=3(x-5)\\y=3x-15\ \ \ \ Eqn\ 4$

Putting value of y and z from Eqn 4 and 2 in Eqn 1

$x+(3x-15)+(x-5)=130\\x+3x-15+x-5=130\\5x-20=130\\5x=130+20\\5x=150$

Dividing both sides by 5

$\frac{5x}{5}=\frac{150}{5}\\x=30$

Putting x = 30 in Eqn 2

$z=30-5\\z=25$

Putting z=25 in Eqn 3

$y=3(25)\\y=75$

Karen has $30, Rafael has $75 and Shen has $25.

Keywords: linear equations, substitution method

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3 years ago

A rancher needs to enclose two adjacent rectangular corrals, one for cattle and one for sheep. If the river forms one side of t

Harrizon [31]

<h3>Width = 55 yards </h3><h3>Length = 165 yards</h3><h3>Maximized area = 9075 sq yd</h3>

Step-by-step explanation:

Here, the total length of fencing available = 390 yd

Let L = length of the side parallel to river

W = width of other 3 sides.

So, total fencing L + 3 W = 390 yd

or, L = 390 - 3 W

Now, Area of the field = L x W

= (390 - 3 w) (W)

or, A = -3 W² + 330 W

The maximum value of above function is at W = $(\frac{-b}{2a} ) = \frac{-330}{2\times (-3)} = 55$

So, W = 55 yards

Now, L = (390 - 3 (55) ) = 165 yards

Now, maximized area = L x W

= 55 x 165 = 9075 sq yds

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4 years ago