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2 years ago

5

The path of a firecracker is modeled by the equation h(t) = -t^2 + 19t + 14, where h(t) is the hight, in feet, of the firecracke

r at any given time, t. What is the hight of the firecracker after 4 seconds from launch.
A. 63 feet
B. 68 feet
C. 70 feet
D. 74 feet

1 answer:

netineya [11]2 years ago

5 0

The answer to this question is 68 feet.

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3 years ago

shepuryov [24]

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lapo4ka [179]

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