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andre [41]
3 years ago
10

Two brothers leave from the same point driving in opposite​ directions, the first brother driving at 55 miles per hour and the s

econd at 50 mph. The first brother has a​ one-hour head start. If each brother has a communication device that allows him to talk to the other for up to a 210​-mile ​range, how long will they be able to talk to each​ other?
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
3 0

Answer: they would be able to talk to each other for 1.5 hours

Step-by-step explanation:

If each brother has a communication device that allows him to talk to the other for up to a 210​-mile ​range, by the time they are 210 miles apart, they won't be able to communicate to each other. This means that they would have travelled a total distance of 210 miles.

Let t represent the time it takes either brothers to travel his own distance.

the first brother driving at 55 miles per hour. If the first brother has a​ one-hour head start, this means that the time spent by the first brother is (t + 1) hour.

Distance = speed × time

Distance travelled by the first brother is

55(t + 1) = 55t + 55

The second brother was driving at 55 miles per hour. This means that distance travelled by the second brother in t hours is

50t

Since the total distance covered is 210 miles, then

55t + 55 + 50t = 210

105t = 210 - 55 = 155

t = 155/105 = 1.476 hours

Approximately 1.5 hours

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2 years ago
There has been much media coverage of the high cost of medicinal drugs in the United States. One concern is the large variation
umka21 [38]

Data for the question :

102.05 99.85 112.3 97.15 111.23 105.37 105.64 106.5 102.97 107.82 106.36 111.24 107.28 114.14 106.28 106.96 98.25 111.55 107.75 101.02 101.12 97.7 97.66 100.54 115.77 112.91 111.04 112.15 102.87 101.14 107.13 108.56 109.56 103.57 108.68 104.59 116.74 116.22 100.22 103.97 111.2 109.34 115.78 101.59 107.93 104.23 96.25 103.84 102.47 102.96 99.26 101.42 108.58 107.69 99.88 102.71 111.25 99.4 117.04 106.35 110.44 102.34 107.25 107.63 105.2 109.14 115.54 101.51 108.49 112.32 109.27 97.54 102.46 105.94 109.42 111.05 102.63 106.99 102.03 108.84 118.8 108.64 95.35 105.47 104.45 102.15 111.4 108.27 104.82 108.4 109.05 116.11 103.7 121.2 99.62 102.81 109.56 103.35 113.02 103.79

Answer:

Range = 25.35

Variance = 29.46

Standard deviation = 5.43

The variation in price of Prozac is high

Step-by-step explanation:

The range of the data :

Maximum - Minimum.

121.2 - 95.35 = 25.35

The variance, s :

s² = Σ(X - m²) / n - 1

Mean, m = Σx / n

X = individual data point

m = mean of data

n = sample size

Using a calculator of save time and ensure accuracy :

s² = 29.45522

The standard deviation, s

s = sqrt(variance)

s = sqrt(s²)

s = sqrt(29.45522)

s = 5.42726.

The range, variance and standard deviation, all measure the degree of variation in a dataset. The values of these statistical measure obtain for the price of 1 product across different pharmaceutical stores, suggests thatvthe variation in price is high;

With a range of about 25.35 and standard deviation of 5.43

4 0
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Answer:

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B)  7 ; which is a different expression from (1)

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C) 7^x   (Same as (1))

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E) \dfrac{7^x\times3^x}{3^x}=7^x   ; which is same as (1)

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F) 3^x  ; which is not same as expression (1)

Hence, option F is incorrect.

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