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andre [41]
3 years ago
10

Two brothers leave from the same point driving in opposite​ directions, the first brother driving at 55 miles per hour and the s

econd at 50 mph. The first brother has a​ one-hour head start. If each brother has a communication device that allows him to talk to the other for up to a 210​-mile ​range, how long will they be able to talk to each​ other?
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
3 0

Answer: they would be able to talk to each other for 1.5 hours

Step-by-step explanation:

If each brother has a communication device that allows him to talk to the other for up to a 210​-mile ​range, by the time they are 210 miles apart, they won't be able to communicate to each other. This means that they would have travelled a total distance of 210 miles.

Let t represent the time it takes either brothers to travel his own distance.

the first brother driving at 55 miles per hour. If the first brother has a​ one-hour head start, this means that the time spent by the first brother is (t + 1) hour.

Distance = speed × time

Distance travelled by the first brother is

55(t + 1) = 55t + 55

The second brother was driving at 55 miles per hour. This means that distance travelled by the second brother in t hours is

50t

Since the total distance covered is 210 miles, then

55t + 55 + 50t = 210

105t = 210 - 55 = 155

t = 155/105 = 1.476 hours

Approximately 1.5 hours

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15 goes into 18 once with 3 remainder.

18/15-15/15=3/15=1/5

So the answer is:
1 \frac{1}{5}
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3 years ago
I need help asap;):)
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Newton discovered that sunlight has many colors when it passes through a prism.

I hope this helped! Mark me Brainliest! :) -Raven❤️
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Among 35 students in a class, 20 of them earned A's on the midterm exam, 13 earned A's on the nal exam, and 12 did not earn A's
enyata [817]

Answer:

The correct answer is "\frac{2}{7}".

Step-by-step explanation:

According to the question,

Number of students,

= 35

A ! mid term A,

n(A) = 20

B : final A,

n(B) = 13

Didn't start,

n(A^c \cap B^c) = 12

Now,

⇒ n(A \cup B)=35-12

                   =23

then,

⇒ n(A \cup B)=20+13-23

                   =10

hence,

The probability will be:

⇒ P(A \cap B)=\frac{10}{35}

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7 0
3 years ago
Approximate the change in the volume of a sphere when its radius changes from r= 5ft to r= 5.1ft (v(r)= 3/4 pi r^3)?
leva [86]

Answer:

18.03 cubic feet

Step-by-step explanation:

Hello,

Step 1

find the volume of the sphere when radius= 5 ft

v(r)= \frac{3}{4} \pi r^3\\v(5)= \frac{3}{4}\pi (5\ ft)^3\\v(5)= \frac{3}{4}\pi *125\ ft^{3} \\v(5)=294.52\ cubic\ feet\\

Step 2

find the volume of the sphere when radius= 5.1 ft

v(r)= \frac{3}{4}\pi r^3\\v(5.1)= \frac{3}{4} \pi (5.1\ ft)^3\\v(5.1)= \frac{3}{4}\pi *132.651\ ft^{3} \\v(5.1)=312.551\ cubic\ feet\\\\

Step 3

Compare the Volumes to find the change

\frac{v(r_{2})}{v(r_{1})} =\frac{312.551}{294.52} =1.06

the volumen of the sphere with radius = 5.1 is 1.06 times bigger than the first one(r=5)

Now, find the change

change= {v(r_{2})-{v(r_{1})}} \\change=312.551\ cubic\ feet\ -294.52 cubic feet \\ change=18.031\ cubic\ feet

change=18.03 cubic feet

Have a great day.

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nignag [31]

Step-by-step explanation:

in my skul, we wud say dat 4 centimeters on the map is equal to 10 kilometers on actual ground

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2 years ago
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