Answer: y=5x+4
Step-by-step explanation:
With the given slope and y-intercept, all we have to do is plug those values into y=mx+b. M stands for slope, and b stands for y-intercept.
y=5x+4
![\frac{n}{12}=10](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B12%7D%3D10)
Multiply both sides of the equation by 12
![\frac{n}{12}\times12=10\times12](https://tex.z-dn.net/?f=%5Cfrac%7Bn%7D%7B12%7D%5Ctimes12%3D10%5Ctimes12)
Answer:
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.
This means that ![n = 1067, \pi = \frac{74}{1067} = 0.069](https://tex.z-dn.net/?f=n%20%3D%201067%2C%20%5Cpi%20%3D%20%5Cfrac%7B74%7D%7B1067%7D%20%3D%200.069)
80% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 - 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.059](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.069%20-%201.28%5Csqrt%7B%5Cfrac%7B0.069%2A0.931%7D%7B1067%7D%7D%20%3D%200.059)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.069 + 1.28\sqrt{\frac{0.069*0.931}{1067}} = 0.079](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.069%20%2B%201.28%5Csqrt%7B%5Cfrac%7B0.069%2A0.931%7D%7B1067%7D%7D%20%3D%200.079)
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
<h2>C is the correct answer</h2><h2></h2><h3>The amount of money <u>depends</u> on how many lawns he mows.</h3><h3></h3><h3><em>Please let me know if I am wrong.</em></h3>