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densk [106]
2 years ago
10

How many years will it take a major hamburger fast food chain to sell 45,000,000 burgers if it sells approximately 12,350 burger

s per day? Show work
Mathematics
2 answers:
TEA [102]2 years ago
8 0
1 day.....12,350 b \\ x...........45,000,000b \\\\ x=\frac{1*45,000,000}{12,350} \\\\ x=3,643.7 :365 \  (days) \\\\ x=9,98 \ days \\\\ \boxed{x=9,98\approx 10 \ years}
S_A_V [24]2 years ago
4 0
If a burger joint sells 12,350 burgers a day, it will take about 10 years to sell 45,000,000 burgers. I say this because 45,000,000 divided by 12,350 is 3643.72. That is how many days it would take to sell 45,000,000 burgers. Now, if you divide 3643.72 by 365 you get 9.98. 9.98 is how many years it would take to sell 45,000,000 burgers.
Hope this helps! :)
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What is m <br> angle 1?<br> 35°<br> 40°<br> 55°<br> 70°
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Answer:

  (b)  40°

Step-by-step explanation:

Angle x and the one marked 70° are alternate interior angles, so are congruent. The sum of the two base angles of the isosceles triangle is ...

  x° +x° = 70° +70° = 140°

So, the remaining angle 1 in the triangle is ...

  180° -140° = 40°

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5 0
2 years ago
In April 1974, Steve Prefontaine completed a 10 km race in a time of 27 min, 43.6 s. Suppose "Pre" was at the 7.15 km mark at a
ELEN [110]

Answer:

  0.2583 m/s²

Step-by-step explanation:

The relationship between speed, distance, and time is ...

  speed = distance/time

Of course, the relationship between the various units of measure is ...

  • 1 km = 1000 m
  • 1 min = 60 s

The average speed for the first 7.15 km was ...

  (7150 m)/(1500 s) = 4 23/30 m/s

The acceleration is considered to be uniform over the 60-second period. The distance traveled during that time will be the same as the distance traveled at the initial speed for 30 s plus that traveled at the final speed for 30 s. That is, we can compute the final speed as though "Pre" ran 25.5 minutes (1530 s) at his initial speed and the remaining time (133.6 s) at his final speed.

The distance for 25.5 minutes at 4 23/30 m/s is ...

  (1530 s)(143/30 m/s) = 7293 m

The remaining distance is then ...

  10,000 -7,293 = 2,707 . . . meters

And the final speed is ...

  (2707 m)/(133.6 s) ≈ 20.262 m/s

The acceleration is the change in speed divided by the time period:

  (20.262 m/s -4.767 m/s)/(60 s) ≈ 0.2583 m/s²

_____

<em>Comment on these numbers</em>

According to this scenario, Pre's speed for the last 2000 meters, sustained for more than a minute, was more than 20 m/s -- about <em>double the world record</em> speed for a 100 meter sprint. It was a little more than <em>4 times</em> his speed for the first 25 minutes.

5 0
3 years ago
I’ll give you an extra 60 points please me within 5 minutes
azamat

Answer: (3p^2 + 1) . (p^3 +4)

Step-by-step explanation:

Area of a rectangle equals length multiplied by width. Given length as 3p^2 + 1 and width as p^3 + 4

Area = 3p^2 + 1) . (p^3 +4)

This is so as 4 is not a cube and cannot be factored.

I hope this helps.

7 0
2 years ago
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