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VladimirAG [237]
2 years ago
9

X is an integer and satisfies the following inequality. 5(x+4)<32 What is the maximum possible value for x?

Mathematics
1 answer:
mars1129 [50]2 years ago
5 0

Answer:

c.2

Step-by-step explanation:

5(x+4)<32

5(2+4)<32

10+20<30

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20 is equal to 5 less than twice a number.
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Actually solving the problem, we can start by adding 5 to both sides, resulting in 2n=25. Next, we can divide both sides by 2 to get n=12.5
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Answer:

a. C(x) = $16, if 0 ≤ x ≤ 10

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We choose a 4-digit number randomly. What is the probability that all its digits are even? help asap
Vlad1618 [11]

Answer:

It's very simple. In 4 decimal digits there are 10,000 (0000 to 9999) possible values. The odds of any one of them coming up randomly is one in 10,000. A specific "4 digit number" would have 1/9000 chance, since there are 9000 4 digit numbers (1000-9999).

Step-by-step explanation:

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Answer: Therefore it must be the first one, 40

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3 years ago
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