All categories

2 years ago

Using the following graph, find f(0) and f(-2)

Mathematics

2 answers:

larisa86 [58]2 years ago

8 0

Answer:

f(0) = 0

f(-2) = 1

Step-by-step explanation:

f(0) means the value of f when x = 0. The line is the result of equation f for all points shown on the graph. Look for the values at x = 0 and x = -2.

They are (0.0) and (-2,1). This can be written as:

f(0) = 0

f(-2) = 1

laila [671]2 years ago

5 0

F(0) = 0
f(-2) = 1
U look at the x- axis at the 0 and the -2 and then u see the curve where it touched u find the solution

You might be interested in

Please answer. - ejhf khev eveveve

antoniya [11.8K]

Your answer would be 6 because they scored 91, 91, 91, 94, 95, 95. Six grades equal 6 people!
Hope this helped!
:)

5 0

2 years ago

Both questions please and thank you

liberstina [14]

Answer:

"there so pretty it hurts im not talking about boys im talking about girls there so pretty with their bottom up shirts AHHH WOAH AHHH"

Step-by-step explanation:

3 0

2 years ago

What does a trapezium look like

sasho [114]

This is a trapezium with congruent unparallel lines.

5 0

2 years ago

Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).

lions [1.4K]

Check the picture below. so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}$

$(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill$

$\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}$

6 0

1 year ago

Dr.Lee's dentist practices is open for 7 hours each day. His receptionist schedules appointments, allowing 1/2 hour for a cleani

Maurinko [17]

Step-by-step explanation:

Below is an attachment containing the solution.

4 0

2 years ago

Using the following graph, find f(0) and f(-2) ​

Using the following graph, find f(0) and f(-2)