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wel
3 years ago
8

C. 20 people show up to the party, and Robert decides to give them each the

Mathematics
1 answer:
Marina86 [1]3 years ago
5 0

Answer:

Step-by-step explanation:3/5 of the pizza

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Find the value of x and the value of y
steposvetlana [31]

Answer:

B.   x = 7, y = 4√2

Step-by-step explanation:

Drop a vertical from the upper left corner

This creates a rectangle and a 45-45-90 triangle

The bottom of the rectangle is 3

The legs of the triangle are 4

Therefor

x = 4 + 3

x = 7

For a 45-45-90 triangle

the hypotenuse = leg * √2

y = 4√2

4 0
3 years ago
Plz help me with this question I don't understand it!!
Sav [38]
9t-7t-t^2
2t-t^2

Hope this helps :)
3 0
3 years ago
If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

it comes

x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}

multiply by 3

3x^2-20x+2*16+5=3x^2-20x+37

4 0
3 years ago
If the m∠1=123° m ∠ 1 = 123 ° and m∠2= (2x+7)° m ∠ 2 = ( 2 x + 7 ) ° , determine the value of x that supports l∥m l ∥ m . Show y
Georgia [21]

Answer:

25

Step-by-step explanation:

Let us assume that m<1 nad m<2 are supplementary. Since the sum of supplementary angles is 180degrees, hence;

<1 + <2= 180

123+2x+7 = 180

130+2x = 180

2x = 180 - 130

2x = 50

x = 50/2

x = 25

Hence the value of x is 25

5 0
2 years ago
What is the scientific notation of 3,482,000,000
alisha [4.7K]
The answer Is 3.482 × 10^9
7 0
3 years ago
Read 2 more answers
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